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Worked Examples · Example 6

Q.Find the compound interest on ₹10,000 for 1 year at 8% per annum, compounded quarterly.

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Given: P=10000P = 10000, nominal R=8%R = 8\% p.a., T=1T = 1 year, compounded quarterly.

Adjust for quarterly compounding. Rate per quarter r=84=2%r = \dfrac{8}{4} = 2\%; number of periods m=4×1=4m = 4 \times 1 = 4.

Method 1 — formula.

A=P(1+r100)m=10000(1.02)4=10000×1.08243216=10824.32.A = P\left(1 + \dfrac{r}{100}\right)^{m} = 10000(1.02)^{4} = 10000 \times 1.08243216 = 10824.32.

So CI=A−P=10824.32−10000=824.32CI = A - P = 10824.32 - 10000 = 824.32.

Method 2 — independent check (quarter-by-quarter).

  • After Q1: 10000×1.02=1020010000 \times 1.02 = 10200.
  • After Q2: 10200×1.02=1040410200 \times 1.02 = 10404. …

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