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Worked Examples · Example 8

Q.A sum of money amounts to ₹9,680 in 2 years at 10% per annum compound interest, compounded annually. Find the principal.

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Given: A=9680A = 9680, R=10%R = 10\% p.a., n=2n = 2 years, compounded annually; find PP.

Method 1 — rearrange the formula.

A=P(1+R100)n  ⇒  P=A(1+R100)n=9680(1.1)2=96801.21=8000.A = P\left(1 + \dfrac{R}{100}\right)^{n} \;\Rightarrow\; P = \dfrac{A}{\left(1 + \frac{R}{100}\right)^{n}} = \dfrac{9680}{(1.1)^{2}} = \dfrac{9680}{1.21} = 8000. …

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