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Worked Examples · Example 1

Q.A firm employs labour (LL) as its only variable factor on a fixed plot of land. The total product schedule is: L=1→TP=10L=1 \to TP=10; L=2→TP=24L=2 \to TP=24; L=3→TP=39L=3 \to TP=39; L=4→TP=52L=4 \to TP=52; L=5→TP=60L=5 \to TP=60; L=6→TP=60L=6 \to TP=60; L=7→TP=56L=7 \to TP=56. Compute the Average Product and Marginal Product at each level, and identify the three stages of production.

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Given: the TP schedule for labour L=1L=1 to 77.

Step 1 — Compute Average Product, AP=TP/LAP=TP/L:

  • L=1L=1: 10/1=1010/1=10
  • L=2L=2: 24/2=1224/2=12
  • L=3L=3: 39/3=1339/3=13
  • L=4L=4: 52/4=1352/4=13
  • L=5L=5: 60/5=1260/5=12
  • L=6L=6: 60/6=1060/6=10
  • L=7L=7: 56/7=856/7=8

Step 2 — Compute Marginal Product, MP=TPn−TPn−1MP=TP_n-TP_{n-1} (taking TP0=0TP_0=0):

  • L=1L=1: 10−0=1010-0=10
  • L=2L=2: 24−10=1424-10=14
  • L=3L=3: 39−24=1539-24=15
  • L=4L=4: 52−39=1352-39=13
  • L=5L=5: 60−52=860-52=8
  • L=6L=6: 60−60=060-60=0
  • L=7L=7: 56−60=−456-60=-4

Step 3 — Assemble the table:

LLTPTPAP=TP/LAP=TP/LMP=ΔTPMP=\Delta TP
1101010
2241214
3391315
4521313
560128
660100
7568-4

Step 4 — Identify the stages:

  • Stage I (Increasing Returns): MP rises up to L=3L=3 (MP peaks at 15) and AP keeps rising to its own maximum of 13 at L=4L=4. This is the increasing-returns stage.
  • Stage II (Diminishing Returns): from L=4L=4 (where AP is maximum) to L=6L=6 (where MP=0MP=0 and TPTP is at its maximum of 60), MP is falling but still positive, so TP is still rising, at a decreasing rate.
  • Stage III (Negative Returns): at L=7L=7, MP is negative (−4-4) and TP actually falls (from 60 to 56).

Check (independent method — reconstruct TP from MP): cumulatively adding the MP column back gives 10,10+14=24,24+15=39,39+13=52,52+8=60,60+0=60,60−4=5610, 10+14=24, 24+15=39, 39+13=52, 52+8=60, 60+0=60, 60-4=56 — exactly the original TP schedule, confirming the MP figures. And APAP at L=6L=6 is 1010, matching MPMP at L=1L=1 by coincidence of values only; more usefully, note MP=AP=13MP=AP=13 at L=4L=4, precisely where AP is maximum, consistent with the MP-AP relationship.

✓Final answer

Stage I up to L=4L=4 (AP maximum, 13); Stage II from L=4L=4 to L=6L=6 (MP=0, TP maximum 60); Stage III at L=7L=7 (MP=-4, TP falling). A rational producer operates in Stage II.

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