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Exercises · Q13

Q.A manufacturer's total cost is a linear function of output. When output is 10 units, total cost is ₹800; when output is 20 units, total cost is ₹1300. Find the cost function C(x)C(x) and state the fixed cost.

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Since total cost is a linear function of output, write C(x)=mx+cC(x) = mx+c, where mm is the variable cost per unit and cc is the fixed cost. We are given two points on this line: (10,800)(10, 800) and (20,1300)(20, 1300).

Finding mm (the slope):

m=1300−80020−10=50010=50m = \frac{1300-800}{20-10} = \frac{500}{10} = 50

So the variable cost per unit is ₹50₹50, and C(x)=50x+cC(x) = 50x + c so far.

Finding cc (the fixed cost): substitute either known point into C(x)=50x+cC(x)=50x+c. Using (10,800)(10,800):

800=50(10)+c800 = 50(10) + c

800=500+c800 = 500 + c

c=300c = 300

So the cost function is

C(x)=50x+300C(x) = 50x + 300

Dual check using the other point, (20,1300)(20, 1300):

C(20)=50(20)+300=1000+300=1300C(20) = 50(20)+300 = 1000+300 = 1300 …

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