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Worked Examples · Example 5

Q.A firm's cost function is C(x)=50x+2000C(x) = 50x + 2000 and its revenue function is R(x)=80xR(x) = 80x, where xx is the number of units produced and sold. Find the profit function P(x)P(x) and the break-even quantity.

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The profit function is defined as revenue minus cost:

P(x)=R(x)−C(x)=80x−(50x+2000)=80x−50x−2000=30x−2000P(x) = R(x) - C(x) = 80x - (50x+2000) = 80x - 50x - 2000 = 30x - 2000

So P(x)=30x−2000P(x) = 30x - 2000 — a linear function of xx, since both R(x)R(x) and C(x)C(x) are linear.

Break-even quantity: the break-even point is where profit is exactly zero, i.e. P(x)=0P(x)=0:

30x−2000=030x - 2000 = 0

30x=200030x = 2000

x=200030=2003≈66.67 unitsx = \frac{2000}{30} = \frac{200}{3} \approx 66.67 \text{ units}

Since a fraction of a unit cannot actually be produced, the firm needs to sell at least 6767 whole units to move from a loss into a genuine profit; at exactly 662366\tfrac23 units the firm's revenue and cost are equal on paper. …

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