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Question 21 of 71
Q.

(b) From the following particulars of Firm AA and Firm BB, find out the firm that pays larger amount as monthly wages:

ParticularsFirm AFirm B
No. of wage-earners550650
Average monthly wages (in rupees)5,0004,500
ChseodishaCHSE Odisha Plus Two (Class 12) Commerce Board 2019Subjective· 3mImportance★★★★★
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Firm B pays the larger total monthly wage bill, Rs. 29,25,000.

Total monthly wages == (number of wage-earners) ×\times (average monthly wage), since xˉ=∑xN⇒∑x=Nxˉ\bar{x} = \dfrac{\sum x}{N} \Rightarrow \sum x = N\bar{x}.

Firm A:

550×5000=Rs. 27,50,000.550 \times 5000 = \text{Rs. } 27{,}50{,}000.

Firm B:

650×4500=Rs. 29,25,000.650 \times 4500 = \text{Rs. } 29{,}25{,}000.

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