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Question 45 of 71
Q.

From the following data, calculate the median, second quartile and the fifth decile :

Value (x)1020304050607080
Frequency2392010854
ChseodishaCHSE Odisha Plus Two (Class 12) Commerce Board 2022Subjective· 3mImportance★★★★★est
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N=61N=61; the 31st item gives Median =Q2=D5=40=Q_2=D_5=40.

Build the cumulative frequency (c.f.) table:

xxffc.f.
1022
2035
30914
402034
501044
60852
70557
80461

Total N=∑f=61N=\sum f=61.

Median. Size of the median item =N+12=622=31=\dfrac{N+1}{2}=\dfrac{62}{2}=31st item. The c.f. just reaching or exceeding 3131 is 3434 (against x=40x=40), since items 1515 to 3434 all take the value 4040. So

Median=40.\text{Median}=40.

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