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Question 58 of 71
Q.

Find out the median of the following distribution :

Marks20253035404550
No. of Students18303245251713
ChseodishaCHSE Odisha Plus Two (Class 12) Commerce Board 2023Subjective· 3mImportance★★★★★est
82% · 58/71 Questions
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N=180N=180, N/2=90N/2=90; the cumulative frequency first crosses 9090 at marks =35=35, so median =35=35.

Step 1 — form the cumulative frequency (c.f.) table:

MarksfCumulative frequency
201818
253048
303280
3545125
4025150
4517167
5013180

Step 2 — total frequency N=180N=180, so

N2=1802=90\dfrac{N}{2}=\dfrac{180}{2}=90

…

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