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Exercises · Q14

Q.For a certain distribution, the arithmetic mean is 45 and the median is 48. Estimate the mode using the empirical relationship, and verify your answer is internally consistent.

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Given: Mean =45=45, Median =48=48.

Mode≈3 Median−2 Mean=3(48)−2(45)=144−90=54\text{Mode} \approx 3\,\text{Median} - 2\,\text{Mean} = 3(48) - 2(45) = 144 - 90 = 54

Independent cross-check — rearrange and verify: the empirical relationship can be rearranged to solve for the median from the mode and mean: Median≈Mode+2 Mean3\text{Median} \approx \dfrac{\text{Mode}+2\,\text{Mean}}{3}. Substituting the estimated mode back in:

Median≈54+2(45)3=54+903=1443=48\text{Median} \approx \frac{54 + 2(45)}{3} = \frac{54+90}{3} = \frac{144}{3} = 48 …

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