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Exercises · Q11

Q.The average marks of 20 students in Section A is 50, and the average marks of 30 students in Section B is 60. Find the combined average marks of both sections together.

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✓ Free question

Given: n1=20n_1=20, Xˉ1=50\bar{X}_1=50; n2=30n_2=30, Xˉ2=60\bar{X}_2=60.

Xˉ12=n1Xˉ1+n2Xˉ2n1+n2=20(50)+30(60)20+30=1000+180050=280050=56\bar{X}_{12} = \frac{n_1\bar{X}_1+n_2\bar{X}_2}{n_1+n_2} = \frac{20(50)+30(60)}{20+30} = \frac{1000+1800}{50} = \frac{2800}{50} = 56

Independent cross-check (reasonableness check): the combined mean must always lie BETWEEN the two group means (50 and 60), and closer to whichever group is LARGER. Since Section B (30 students, mean 60) is larger than Section A (20 students, mean 50), the combined mean should lie closer to 60 than to 50. The computed value, 56, indeed lies between 50 and 60 and is closer to 60 — consistent with Section B's larger weight.

✓Final answer

Combined average marks of both sections = 56 (correctly closer to Section B's higher mean, since Section B has more students).

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