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Exercises · Q12

Q.A student scored 80 marks in a subject weighted 3, 70 marks in a subject weighted 2, and 90 marks in a subject weighted 1. Find the weighted arithmetic mean of the marks.

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Direct method:

Marks (xx)Weight (ww)wxwx
803240
702140
90190
Total6470

Xˉw=ΣwxΣw=4706=78.33\bar{X}_w = \frac{\Sigma wx}{\Sigma w} = \frac{470}{6} = 78.33

Independent cross-check — deviation method: take A=80A=80, deviations d=x−Ad=x-A: for 80, d=0d=0; for 70, d=−10d=-10; for 90, d=10d=10.

Xˉw=A+ΣwdΣw=80+(0)(3)+(−10)(2)+(10)(1)6=80+0−20+106=80−1.67=78.33\bar{X}_w = A + \frac{\Sigma wd}{\Sigma w} = 80 + \frac{(0)(3)+(-10)(2)+(10)(1)}{6} = 80 + \frac{0-20+10}{6} = 80 - 1.67 = 78.33 …

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