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Question 22 of 42
Q.

From the following information, find correlation coefficient between heights and weights.

Height (cm) xx155165158162153160
Weight (kg) yy536356605260
Gujarat GsebGujarat Board (GSEB) HSC Commerce Board 2022Subjective· 5mImportance★★★★★
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With u=x−158, v=y−56u=x-158,\ v=y-56: Σu=5,Σv=8,Σu2=103,Σv2=106,Σuv=102\Sigma u=5,\Sigma v=8,\Sigma u^2=103,\Sigma v^2=106,\Sigma uv=102, n=6n=6; r=572593×572≈0.982r=\dfrac{572}{\sqrt{593\times572}}\approx\mathbf{0.982}.

Data: xx (height): 155,165,158,162,153,160; yy (weight): 53,63,56,60,52,60; n=6n=6.

Take assumed means A=158A=158 for xx, B=56B=56 for yy; let u=x−158u=x-158, v=y−56v=y-56.

xxyyu=x−158u=x-158v=y−56v=y-56u2u^2v2v^2uvuv
15553-3-3999
1656377494949
1585600000
1626044161616
15352-5-4251620
16060244168
Σ58103106102

Karl Pearson's formula (invariant under change of origin):

r=n Σuv−Σu Σv[n Σu2−(Σu)2][n Σv2−(Σv)2].r=\frac{n\,\Sigma uv-\Sigma u\,\Sigma v}{\sqrt{\big[n\,\Sigma u^2-(\Sigma u)^2\big]\big[n\,\Sigma v^2-(\Sigma v)^2\big]}}.

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