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Q.The following data is available for two variables rainfall in mm(X) and yield of crop Qtl/Hec(Y): n=10, xˉ=120, yˉ=150, Sx=30, Sy=40n = 10,\ \bar{x} = 120,\ \bar{y} = 150,\ S_x = 30,\ S_y = 40 and Σxy=1,89,000\Sigma xy = 1{,}89{,}000. Find correlation coefficient.

Gujarat GsebGujarat Board (GSEB) HSC Commerce Board 2026Subjective· 3mImportance★★★★★
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Cov=18900010−120×150=900\text{Cov}=\tfrac{189000}{10}-120\times150=900; r=90030×40=0.75r=\dfrac{900}{30\times40}=0.75.

Karl Pearson's coefficient can be written as r=Cov(x,y)Sx Syr=\dfrac{\text{Cov}(x,y)}{S_x\,S_y}, where

Cov(x,y)=Σxyn−xˉ yˉ.\text{Cov}(x,y)=\frac{\Sigma xy}{n}-\bar x\,\bar y.

Substituting Σxy=1,89,000, n=10, xˉ=120, yˉ=150\Sigma xy=1{,}89{,}000,\ n=10,\ \bar x=120,\ \bar y=150:

Cov(x,y)=18900010−(120)(150)=18900−18000=900.\text{Cov}(x,y)=\frac{189000}{10}-(120)(150)=18900-18000=900. …

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