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Question 34 of 42
Q.

The following information is obtained to study the relationship between the advertisement cost and the sales of electric fans of the companies manufacturing electric fans. Find the correlation coefficient between advertisement cost and sales by Karl-Pearson's method :

CompanyABCDEF
Advertisement cost (lakh ₹)1401208010080180
Sales of electric fans (crore ₹)354515402050
Gujarat GsebGujarat Board (GSEB) HSC Commerce Board 2025Subjective· 5mImportance★★★★★
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Using the raw-sum formula, r=nΣxy−ΣxΣy[nΣx2−(Σx)2][nΣy2−(Σy)2]=1310016226.21≈0.81r = \dfrac{n\Sigma xy - \Sigma x \Sigma y}{\sqrt{[n\Sigma x^2 - (\Sigma x)^2][n\Sigma y^2 - (\Sigma y)^2]}} = \dfrac{13100}{16226.21} \approx 0.81.

GSEB Class-12 Statistics, Linear Correlation (Karl Pearson):

Let xx = advertisement cost, yy = sales, n=6n = 6.

Companyxxyyx2x^2y2y^2xyxy
A140351960012254900
B120451440020255400
C801564002251200
D100401000016004000
E802064004001600
F180503240025009000
Total70020589200797526100

Karl Pearson's coefficient:

r=nΣxy−Σx Σy[ nΣx2−(Σx)2 ] [ nΣy2−(Σy)2 ]r = \frac{n\Sigma xy - \Sigma x \, \Sigma y}{\sqrt{[\,n\Sigma x^2 - (\Sigma x)^2\,]\,[\,n\Sigma y^2 - (\Sigma y)^2\,]}}

Numerator:

nΣxy−ΣxΣy=6(26100)−(700)(205)=156600−143500=13100n\Sigma xy - \Sigma x \Sigma y = 6(26100) - (700)(205) = 156600 - 143500 = 13100

Denominator terms: …

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