Skip to content
Question 14 of 41

Q.Fit a linear equation from the following data for variable (y)(y) of a time series n=4n = 4, Σy=270\Sigma y = 270, Σty=734\Sigma ty = 734.

Gujarat GsebGujarat Board (GSEB) HSC Commerce Board 2020Subjective· 3mImportance★★★★★
34% · 14/41 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Even nn: code t=−3,−1,1,3t = -3,-1,1,3 (∑t=0\sum t = 0, ∑t2=20\sum t^2 = 20); a=270/4=67.5a = 270/4 = 67.5, b=734/20=36.7b = 734/20 = 36.7; y^=67.5+36.7t\hat y = 67.5 + 36.7t.

The straight-line trend is y^=a+bt\hat{y} = a + bt. For n=4n = 4 (an even number of years) we take the time origin at the middle and use a half-year unit, so the coded values are

t=−3, −1, 1, 3  ⟹  ∑t=0,∑t2=9+1+1+9=20.t = -3,\ -1,\ 1,\ 3 \implies \sum t = 0,\quad \sum t^2 = 9+1+1+9 = 20.

Because ∑t=0\sum t = 0, the normal equations simplify to:

a=∑yn=2704=67.5a = \frac{\sum y}{n} = \frac{270}{4} = 67.5

b=∑ty∑t2=73420=36.7b = \frac{\sum t y}{\sum t^2} = \frac{734}{20} = 36.7

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.