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Question 26 of 41

Q.Obtain the linear equation for trend for a time series with n=7n = 7, ∑y=145.2\sum y = 145.2, ∑ty=637.3\sum ty = 637.3.

Gujarat GsebGujarat Board (GSEB) HSC Commerce Board 2023Subjective· 3mImportance★★★★★
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For n=7n=7 with coded tt (∑t=0, ∑t2=28\sum t=0,\ \sum t^2=28): a=∑yn=20.74a=\frac{\sum y}{n}=20.74, b=∑ty∑t2=22.76b=\frac{\sum ty}{\sum t^2}=22.76; y^=20.74+22.76t\hat y=20.74+22.76t.

Using the method of least squares with time coded so that ∑t=0\sum t=0 (for n=7n=7, take t=−3,−2,−1,0,1,2,3t=-3,-2,-1,0,1,2,3), the normal equations reduce to

a=∑yn,b=∑ty∑t2.a=\frac{\sum y}{n},\qquad b=\frac{\sum ty}{\sum t^2}.

Here ∑t2=(−3)2+⋯+32=9+4+1+0+1+4+9=28\sum t^2=(-3)^2+\dots+3^2=9+4+1+0+1+4+9=28. …

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