Skip to content
Question of 77

Q.Why are the curved roads banked? Obtain an expression for angle of banking of a curved road.

Jammu Kashmir JkboseJammu and Kashmir Board of School Education (Class 11) 2022Subjective· 3mImportance★★★★★
0% · 0/77 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Banking supplies centripetal force via the normal reaction instead of relying purely on friction; for frictionless banking, tan(theta) = v^2/(rg).

Why roads are banked: When a vehicle moves along a curved (horizontal, unbanked) road, the necessary centripetal force is provided entirely by friction between the tyres and the road. This is unreliable, especially at high speed or on a wet/slippery road, and causes excessive tyre wear -- if the required centripetal force exceeds the maximum available friction, the vehicle skids outward. To reduce this dependence on friction, the outer edge of the road is raised above the inner edge -- this is called banking.

Derivation of the angle of banking (ideal case, ignoring friction):

Consider a vehicle of mass m moving with speed v on a road of radius r, banked at angle theta to the horizontal. The normal reaction N acts perpendicular to the road surface. Resolve N into a vertical component (N cos theta) and a horizontal component (N sin theta):

Vertical equilibrium (no vertical acceleration):

N cos(theta) = mg ... (1)

Horizontal direction (this component provides the centripetal force):

N sin(theta) = m v^2 / r ... (2)

Dividing (2) by (1): …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.