Q.A screen is placed 90 cm from an object. The image of the object on the screen is formed by a convex lens at two different locations separated by 20 cm. Determine the focal length of the lens.
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🔒 Start your 14-day free trial to unlock the full solution →Concept understanding — Lens Maker's Formula
The Intuition: Why a Lens Bends Light
A lens works because light slows down when it enters glass. When a wavefront hits a curved surface at an angle, different parts of it slow down at different moments, and the wavefront bends. The stronger the curvature, the more it bends.
A lens has two surfaces. Each surface bends light by an amount that depends on its radius of curvature R and the refractive index n of the glass. The net bending — the focal length f — is the combined effect of both surfaces.
If you had a single spherical surface separating air from glass, its contribution to bending power is Rn−1. A lens has two such surfaces: light goes from air into glass at the first surface, then from glass back into air at the second. Because the two surfaces face opposite directions relative to the travelling light, their radii typically carry opposite signs.
This uses the New Cartesian Sign Convention (the one used in NCERT and CBSE): all distances are measured from the optical centre, and the direction the incident light travels in is taken as positive. So R is positive if the centre of curvature lies on the side the light is travelling towards (the outgoing side), and negative if it lies on the side the light is travelling from (the incident side).
The Precise Statement
For a thin lens (thickness negligible compared to the radii), the Lens Maker's Formula is:
f1=(n−1)(R11−R21)
where:
- f is the focal length of the lens (positive for converging, negative for diverging)
- n is the refractive index of the lens material relative to the surrounding medium (usually air)
- R1 is the radius of curvature of the first surface (the one light reaches first)
- R2 is the radius of curvature of the second surface
f1=(n−1)(R11−R21)
How to Apply It: A Worked Example
Take a biconvex lens made of glass (n=1.5) with both surfaces having the same radius of curvature magnitude, 20 cm.
Light travels left to right. The first surface bulges toward the incoming light, so its centre of curvature lies to the right of the surface — on the side the light is travelling towards. By the rule above, R1=+20 cm.
The second surface also bulges outward (away from the lens), so its centre of curvature lies to the left of that surface — on the side the light is travelling from. So R2=−20 cm.
Plug in:
f1=(1.5−1)(201−−201)=0.5×(201+201)=0.5×202=201
So f=+20 cm. Positive means converging — correct for a biconvex lens.
The most common mistake is getting the sign of R2 wrong. For a biconvex lens, R1 is positive and R2 is negative. For a biconcave lens, it's the reverse: R1 negative, R2 positive. Always sketch the lens and mark where each surface's centre of curvature actually sits.
Why the Formula Works (Brief Derivation) …
Concept: Displacement method for focal length of a convex lens.
When object and screen are fixed at a distance D apart, a convex lens forms a sharp image at two positions separated by d. The focal length is given by:
f=4DD2−d2
Step 1: Identify D and d.
D=90 cm (distance between object and screen).
d=20 cm (separation between the two lens positions).
Step 2: Substitute into the formula. …
For a fixed object-screen distance D, a convex lens forms a sharp image at two positions separated by d (displacement method). The focal length is f=4DD2−d2. Here D=90 cm, d=20 cm, so f=3608100−400=3607700≈21.39 cm.
The displacement method for finding the focal length of a convex lens is a classic experiment — and a favourite in exams — because it avoids the need to measure object and image distances separately. The key insight: when the object and screen are fixed at a separation D greater than 4f, there are two distinct lens positions that produce a sharp image on the screen. One gives a magnified image, the other a diminished one. The distance between these two positions, d, together with D, directly gives f.
Why does this happen? For a given object distance u, the lens formula f1=u1+v1 with v=D−u becomes a quadratic in u. Two real roots exist when D>4f, and the difference between them is exactly d=D2−4fD. Rearranging gives the neat formula.
Let’s work through it step by step.
- Set up the geometry. Object and screen are fixed 90 cm apart. So D=90 cm. Let the lens be at a distance u from the object. Then the image distance from the lens is v=D−u (since the screen is on the other side). The lens formula:
f1=u1+D−u1.
- Form the quadratic in u. Combine the fractions:
f1=u(D−u)D−u+u=u(D−u)D.
So
u(D−u)=Df⇒−u2+Du−Df=0.
Multiply by −1:
u2−Du+Df=0.
- Two solutions — the two lens positions. This quadratic has two roots u1 and u2 (the two object distances for which a sharp image forms). Their sum and product:
u1+u2=D,u1u2=Df.
The distance between the two lens positions is d=∣u1−u2∣.
Using the identity (u1−u2)2=(u1+u2)2−4u1u2, we get
d2=D2−4Df.
- Solve for f. Rearranging: …
Method: Displacement Method (for Convex Lens)
This method is used when a convex lens forms a real image of an object on a fixed screen at two different positions — a classic exam setup.
Step 1: Understand the given data
- Distance between object and screen: D=90 cm
- Distance between the two lens positions: d=20 cm
Step 2: Recall the formula
For the displacement method, the focal length f of the convex lens is given by:
f=4DD2−d2
This formula comes from the fact that for a fixed object-screen distance D, the lens forms a sharp image at two positions separated by d, and the lens formula is applied to both positions.
Step 3: Substitute the values
f=4×90(90)2−(20)2
f=3608100−400
f=3607700
Step 4: Simplify
f=36770=18385
f≈21.39 cm
--- …
Here are the common mistakes students make on this classic displacement method problem, along with how to avoid each.
1. Confusing the two lens positions
Mistake:
Students think the two positions are symmetric about the midpoint, or they try to guess which distance is u and which is v without using the formula.
Why it happens:
The problem says the lens forms a sharp image at two positions separated by 20 cm. Many assume one position is obvious — it is not.
How to avoid:
Use the displacement method formula directly:
If D = distance between object and screen, and d = separation between the two lens positions, then
f=4DD2−d2
Here:
- D=90 cm
- d=20 cm
So:
f=4×90902−202=3608100−400=3607700≈21.39 cm
Key takeaway: Memorise the formula — it saves time and avoids confusion.
2. Forgetting that u and v swap between positions
Mistake:
Students set up u and v for one position, then use the same values for the second position.
Why it happens:
They don’t realise that in the displacement method, the two positions correspond to interchanging object and image distances.
How to avoid:
Remember:
- At position 1: u1, v1
- At position 2: u2=v1, v2=u1
This is the core symmetry. The lens formula f1=u1+v1 gives the same f for both.
3. Using the lens formula incorrectly with the given numbers
Mistake:
Plugging u=90 or v=90 directly into f1=u1+v1.
Why it happens:
They think the 90 cm is either u or v, but it’s actually u+v=D.
How to avoid:
Always write:
u+v=D
Then use the fact that the two positions give u1−u2=d (or v1−v2=d).
Solve the system:
u+v=90
v−u=20
This gives v=55, u=35 (or vice versa). Then:
f1=351+551⟹f≈21.39 cm
4. Sign convention errors
Mistake: …
- JKBOSE Class 12 Annual Regular Examination 2026Set SZ5 marksQ.What is Lens Maker's formula? Derive an expression for Lens Maker's formula for a convex lens. OR State Huygen's Principle. Derive laws of reflection from Huygen's Principle.
›Reveal solutionSolution
The Lens Maker's formula, f1=(μ−1)(R11−R21), is derived by applying single-surface refraction twice, once at each face of the lens. (OR alternative: Huygens' Principle constructs wavefronts from secondary wavelets, and can be used to derive the laws of reflection geometrically.)
Part 1: Lens Maker's Formula
What it is. The Lens Maker's formula relates a lens's focal length f to the refractive index μ of its material (relative to the surrounding medium) and the radii of curvature R1, R2 of its two spherical surfaces — it tells a lens manufacturer what curvatures are needed to grind a lens of a desired focal length.
Derivation for a thin convex lens. Consider a thin lens with two refracting surfaces of radii R1 (first surface, light hits this first) and R2 (second surface), made of material of refractive index μ, surrounded by air (index 1). Let a point object O on the principal axis form an image after refraction at each surface in turn.
Step 1 — Refraction at the first surface (radius R1), treating it alone (ignoring the second surface for now), forming a virtual intermediate image I1 at distance v1:
v1μ−u1=R1μ−1
Step 2 — Refraction at the second surface (radius R2): the image I1 from step 1 now acts as the object for this second refraction (light going from the denser lens medium μ back into air, index 1), forming the final image I at distance v:
v1−v1μ=R21−μ
Step 3 — Add the two equations (the μ/v1 terms cancel):
v1−u1=(μ−1)(R11−R21)
Step 4 — Apply the lens definition. When the object is at infinity (u→∞), the image forms at the focus (v=f), so v1−u1→f1. Substituting:
f1=(μ−1)(R11−R21)
This is the Lens Maker's formula, and it also leads to the general thin lens formula v1−u1=f1.
OR: Huygens' Principle and the Laws of Reflection
Huygens' Principle. Every point on a given wavefront (a surface of constant phase) acts as a source of new secondary wavelets, which spread out in all directions with the speed of the wave in that medium. The new wavefront at any later time is given by the forward "envelope" (common tangent surface) of all these secondary wavelets.
Deriving the laws of reflection. Consider a plane wavefront AB incident on a reflecting surface MN at angle of incidence i, with A striking the surface first while B is still travelling. …
- JKBOSE Class 12 Annual Regular Examination 2023Set ANNUAL5 marksQ.Stating the assumptions made and convention of signs used, derive the lens maker's formula in case of a double convex lens. OR Define fringe width. Derive an expression for fringe width in Young's double slit experiment of interference of light.
›Reveal solutionSolution
The lens maker's formula, 1/f = (n21-1)(1/R1 - 1/R2), is derived by applying refraction at each of the two spherical surfaces of a thin lens in turn. (OR: Fringe width beta = lambdaD/d is derived from the path-difference condition for constructive/destructive interference in Young's double-slit experiment.)
Derivation of Lens Maker's Formula (for a thin double convex lens):
Assumptions: (i) The lens is thin, so the two refracting surfaces are close enough that the lateral displacement of the ray inside the lens can be neglected. (ii) Only paraxial rays (making small angles with the principal axis) are considered. (iii) The medium on both sides of the lens is the same (say, refractive index n1), and the lens material has refractive index n2.
Sign convention: All distances are measured from the pole/optical centre of the surface; distances measured in the direction of the incident light are taken positive, against it negative. For a double convex lens, the first surface (facing the incident light) is convex towards the object, so its radius R1 is positive; the second surface curves the other way, so its radius R2 is negative.
Consider a point object O on the principal axis. Let the first surface (radius R1) refract the light from the object; treating this surface alone, the image I1 formed (a virtual, intermediate image) obeys the single-surface refraction formula:
n2/v1 - n1/u = (n2 - n1)/R1 ... (i)
where u is the object distance and v1 is the image distance for the first surface alone.
This intermediate image I1 now acts as a virtual object for the second surface (radius R2), which refracts the ray back into the surrounding medium n1, forming the final real image I at distance v:
n1/v - n2/v1 = (n1 - n2)/R2 ... (ii)
Adding equations (i) and (ii), the n2/v1 and -n2/v1 terms cancel:
n1/v - n1/u = (n2-n1)/R1 + (n1-n2)/R2 = (n2-n1)*(1/R1 - 1/R2).
Dividing throughout by n1:
1/v - 1/u = (n2/n1 - 1)(1/R1 - 1/R2) = (n21 - 1)(1/R1 - 1/R2), where n21 = n2/n1 is the refractive index of the lens material relative to the surrounding medium.
Now, if the object is placed at infinity (u tends to infinity), the rays refracted by the lens converge (for a convex lens) to the principal focus, so v = f (the focal length). Putting u = infinity, 1/u = 0:
1/f = (n21 - 1)*(1/R1 - 1/R2).
This is the Lens Maker's Formula. It relates the focal length f of a thin lens to the refractive index of its material (relative to the surrounding medium) and the radii of curvature of its two surfaces, and is used by lens manufacturers to design a lens of a required focal length. For a double convex lens (R1 positive, R2 negative), (1/R1 - 1/R2) is positive, so f comes out positive - confirming it is a converging lens.
…
- JKBOSE Class 12 Annual Regular Examination 2021Set SZ5 marksQ.Derive Lens-Maker's formula for convex lens. Write the necessary sign convention used. OR State Huygen's wave principles. Use them to prove laws of refraction of light.
›Reveal solutionSolution
The lens-maker's formula relates a thin lens's focal length to its refractive index and the radii of curvature of its two surfaces, derived by applying single-surface refraction twice.
Sign convention (Cartesian, as used in NCERT): All distances are measured from the optical centre of the lens. Distances measured in the direction of the incident light are taken as positive; distances measured against the direction of incident light are taken as negative. Heights measured upward from the principal axis are positive, downward are negative. For a convex lens, if the centre of curvature of a surface lies on the outgoing-light side, its radius R is positive; if on the incoming-light side, R is negative.
Derivation of lens-maker's formula:
Consider a thin convex lens of refractive index n2 placed in a medium of refractive index n1, with surfaces of radii R1 and R2. Let an object be at O on the principal axis.
Refraction at the first surface (radius R1) forms an image at I1 (treating the second surface as absent), using the single spherical refracting surface formula:
v1n2−un1=R1n2−n1
Refraction at the second surface (radius R2): the image I1 from the first surface now acts as a virtual object for the second surface, forming the final image at I (at distance v):
vn1−v1n2=R2n1−n2
Adding these two equations (the n2/v1 terms cancel):
vn1−un1=(n2−n1)(R11−R21)
Dividing throughout by n1:
v1−u1=(n1n2−1)(R11−R21)=(n21−1)(R11−R21)
When the object is at infinity (u→∞), the image forms at the focus, v=f, giving the general lens formula v1−u1=f1, so:
f1=(n21−1)(R11−R21)
where n21=n2/n1 is the refractive index of the lens material relative to the surrounding medium.
OR — Huygens' principle and laws of refraction:
Huygens' wave principle: Every point on a given wavefront (locus of points vibrating in phase) acts as a source of new secondary wavelets, which spread out in all directions with the speed of the wave in that medium. The new (secondary) wavefront at any later instant is the surface tangent (envelope) to all these secondary wavelets.
Derivation of Snell's law using Huygens' construction:
…
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