Q.(a) Determine the 'effective focal length' of the combination of the two lenses in Exercise 9.10, if they are placed 8.0 cm apart with their principal axes coincident. Does the answer depend on which side of the combination a beam of parallel light is incident? Is the notion of effective focal length of this system useful at all?
🔒You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.
🔒 Start your 14-day free trial to unlock the full solution →Concept understanding — Lens Maker's Formula
The Intuition: Why a Lens Bends Light
A lens works because light slows down when it enters glass. When a wavefront hits a curved surface at an angle, different parts of it slow down at different moments, and the wavefront bends. The stronger the curvature, the more it bends.
A lens has two surfaces. Each surface bends light by an amount that depends on its radius of curvature R and the refractive index n of the glass. The net bending — the focal length f — is the combined effect of both surfaces.
If you had a single spherical surface separating air from glass, its contribution to bending power is Rn−1. A lens has two such surfaces: light goes from air into glass at the first surface, then from glass back into air at the second. Because the two surfaces face opposite directions relative to the travelling light, their radii typically carry opposite signs.
This uses the New Cartesian Sign Convention (the one used in NCERT and CBSE): all distances are measured from the optical centre, and the direction the incident light travels in is taken as positive. So R is positive if the centre of curvature lies on the side the light is travelling towards (the outgoing side), and negative if it lies on the side the light is travelling from (the incident side).
The Precise Statement
For a thin lens (thickness negligible compared to the radii), the Lens Maker's Formula is:
f1=(n−1)(R11−R21)
where:
- f is the focal length of the lens (positive for converging, negative for diverging)
- n is the refractive index of the lens material relative to the surrounding medium (usually air)
- R1 is the radius of curvature of the first surface (the one light reaches first)
- R2 is the radius of curvature of the second surface
f1=(n−1)(R11−R21)
How to Apply It: A Worked Example
Take a biconvex lens made of glass (n=1.5) with both surfaces having the same radius of curvature magnitude, 20 cm.
Light travels left to right. The first surface bulges toward the incoming light, so its centre of curvature lies to the right of the surface — on the side the light is travelling towards. By the rule above, R1=+20 cm.
The second surface also bulges outward (away from the lens), so its centre of curvature lies to the left of that surface — on the side the light is travelling from. So R2=−20 cm.
Plug in:
f1=(1.5−1)(201−−201)=0.5×(201+201)=0.5×202=201
So f=+20 cm. Positive means converging — correct for a biconvex lens.
The most common mistake is getting the sign of R2 wrong. For a biconvex lens, R1 is positive and R2 is negative. For a biconcave lens, it's the reverse: R1 negative, R2 positive. Always sketch the lens and mark where each surface's centre of curvature actually sits.
Why the Formula Works (Brief Derivation) …
(a) Effective focal length — trace the parallel beam through each lens (f1=+30 cm convex, f2=−20 cm concave, separation d=8 cm).
Convex side first: parallel rays converge at the convex focus 30 cm away, i.e. 30−8=22 cm past the concave lens (virtual object, u=+22 cm):
v1=−201+221=−2201⇒v=−220 cm.
Concave side first: rays diverge from the concave focus 20 cm away, giving a real object for the convex lens at u=−(20+8)=−28 cm:
v1=301−281=−4201⇒v=−420 cm.
The two results (220 cm vs 420 cm) differ, so the effective focal length depends on the side of incidence and is not a useful single number for a separated pair. (The combination formula F1=f11+f21−f1f2d gives F=−300 cm, but only measured from shifting principal planes.) …
Tracing parallel light through the separated pair gives an emergent beam that appears to come from 220 cm (light entering the convex side) or 420 cm (entering the concave side); the two differ, so a single 'effective focal length' is not useful. In (b) the system gives m=2315≈0.65 and an image ≈0.98 cm tall.
(a) Effective focal length
The lenses of Exercise 9.10 are f1=+30 cm (convex) and f2=−20 cm (concave), now d=8.0 cm apart. A single equivalent focal length only describes a pair faithfully when the lenses are in contact; with a gap we trace the beam lens by lens.
Light on the convex lens first. Parallel rays head for the convex focus, 30 cm to its right. That point is 30−8=22 cm beyond the concave lens and acts as a virtual object for it (u=+22 cm):
v1=f21+u1=−201+221=−2201⇒v=−220 cm.
The emergent beam diverges as if from a point 220 cm to the left of the concave lens.
Light on the concave lens first. Parallel rays diverge as if from the concave focus, 20 cm to its left — a real object for the convex lens 8 cm away, u=−(20+8)=−28 cm:
v1=f11+u1=301−281=−4201⇒v=−420 cm.
Now the beam appears to come from 420 cm.
Conclusion. The two answers (220 cm and 420 cm) are different, so the result depends on the side of incidence; the pair cannot be replaced by one thin lens and the notion of a single effective focal length is not useful here. (The algebraic combination F1=f11+f21−f1f2d=−3001 gives F=−300 cm, but this is referred to principal planes that themselves shift with the side of incidence.)
(b) Magnification and image size
Object height ho=1.5 cm, placed 40 cm before the convex lens. …
Method: Sequential Image Formation (Lens-by-Lens Analysis)
This is the standard method for compound lens systems — treat each lens separately, using the image from the first lens as the object for the second lens.
Steps
Step 1: Identify the given data
From Exercise 9.10 (standard NCERT reference):
- Convex lens: f1=+30 cm
- Concave lens: f2=−20 cm
- Separation between lenses: d=8.0 cm
Step 2: For part (a) — Effective focal length
- Use the formula for the effective focal length F of two thin lenses separated by distance d:
F1=f11+f21−f1f2d
- Substitute:
F1=301+(−20)1−(30)(−20)8.0
F1=301−201+6008
F1=60020−30+8=600−2=−3001
- Therefore:
F=−300 cm
Step 3: Does the answer depend on which side the light is incident?
- Yes, the effective focal length formula assumes a specific order of lenses.
- If parallel light is incident from the convex side first, the calculation above holds.
- If incident from the concave side first, the roles of f1 and f2 swap, giving a different F.
- Conclusion: The notion of effective focal length is not very useful here because the system is not a simple equivalent lens — the image position depends on which lens the light hits first.
Step 4: For part (b) — Magnification and image size
- Object distance from convex lens: u1=−40 cm (sign convention: object to left of lens)
- Lens 1 (convex): f1=+30 cm
Using lens formula:
v11−u11=f11
v11=301+−401=1204−3=1201
v1=+120 cm(real image, to the right of convex lens)
- Magnification by lens 1:
m1=u1v1=−40120=−3
Step 5: Image from lens 1 becomes object for lens 2
- Distance between lenses = 8.0 cm
- So, v1=120 cm from lens 1 means it is 120−8=112 cm to the right of lens 2.
- For lens 2 (concave), object distance: u2=+112 cm (object is on the right side — virtual object for lens 2)
Step 6: Lens 2 (concave): f2=−20 cm …
Common Mistakes & How to Avoid Them
Mistake 1: Treating the two-lens system as a single thin lens with a simple formula
The error: Students try to use the formula F1=f11+f21 directly, ignoring the separation between lenses.
Why it's wrong: That formula works only for lenses in contact (separation d=0). Here d=8.0 cm, so you must use the lens combination formula:
F1=f11+f21−f1f2d
How to avoid: Always check if d=0 before using the simple formula. If d=0, use the full formula above.
Mistake 2: Forgetting that effective focal length depends on the side of incidence
The error: Students assume F is the same regardless of which side the light enters from.
Why it's wrong: The effective focal length is different for light entering from the left vs. the right when d=0. The formula above gives F for light incident from the left (first lens = f1). For light from the right, swap f1 and f2 in the formula.
How to avoid:
- For part (a), compute F for both directions explicitly.
- The answer does depend on which side the light is incident — state this clearly.
Mistake 3: Thinking the "effective focal length" concept is always useful
The error: Students assume that once F is found, it can be used like a single lens for any object position.
Why it's wrong: The effective focal length is only meaningful for parallel incident light (object at infinity). For a finite object distance, you cannot use F directly — you must trace the image through each lens step-by-step.
How to avoid: For part (b), do not use F. Instead:
- Find the image from the first lens using v11−u11=f11
- Use that image as the object for the second lens (accounting for separation d)
- Find the final image position and magnification
Mistake 4: Sign convention errors in the two-lens calculation
The error: Students forget to adjust the object distance for the second lens properly.
Why it's wrong: If the first image forms at distance v1 from lens 1, and the lenses are d apart, then the object distance for lens 2 is:
u2=d−v1
(using the Cartesian sign convention consistently)
How to avoid: Draw a clear ray diagram. Label distances from each lens. Always check:
- Is u2 positive or negative?
- Is the object for lens 2 real or virtual?
Mistake 5: Confusing total magnification with individual magnifications
The error: Students add magnifications or forget to multiply them. …
- JKBOSE Class 12 Annual Regular Examination 2026Set SZ5 marksQ.What is Lens Maker's formula? Derive an expression for Lens Maker's formula for a convex lens. OR State Huygen's Principle. Derive laws of reflection from Huygen's Principle.
›Reveal solutionSolution
The Lens Maker's formula, f1=(μ−1)(R11−R21), is derived by applying single-surface refraction twice, once at each face of the lens. (OR alternative: Huygens' Principle constructs wavefronts from secondary wavelets, and can be used to derive the laws of reflection geometrically.)
Part 1: Lens Maker's Formula
What it is. The Lens Maker's formula relates a lens's focal length f to the refractive index μ of its material (relative to the surrounding medium) and the radii of curvature R1, R2 of its two spherical surfaces — it tells a lens manufacturer what curvatures are needed to grind a lens of a desired focal length.
Derivation for a thin convex lens. Consider a thin lens with two refracting surfaces of radii R1 (first surface, light hits this first) and R2 (second surface), made of material of refractive index μ, surrounded by air (index 1). Let a point object O on the principal axis form an image after refraction at each surface in turn.
Step 1 — Refraction at the first surface (radius R1), treating it alone (ignoring the second surface for now), forming a virtual intermediate image I1 at distance v1:
v1μ−u1=R1μ−1
Step 2 — Refraction at the second surface (radius R2): the image I1 from step 1 now acts as the object for this second refraction (light going from the denser lens medium μ back into air, index 1), forming the final image I at distance v:
v1−v1μ=R21−μ
Step 3 — Add the two equations (the μ/v1 terms cancel):
v1−u1=(μ−1)(R11−R21)
Step 4 — Apply the lens definition. When the object is at infinity (u→∞), the image forms at the focus (v=f), so v1−u1→f1. Substituting:
f1=(μ−1)(R11−R21)
This is the Lens Maker's formula, and it also leads to the general thin lens formula v1−u1=f1.
OR: Huygens' Principle and the Laws of Reflection
Huygens' Principle. Every point on a given wavefront (a surface of constant phase) acts as a source of new secondary wavelets, which spread out in all directions with the speed of the wave in that medium. The new wavefront at any later time is given by the forward "envelope" (common tangent surface) of all these secondary wavelets.
Deriving the laws of reflection. Consider a plane wavefront AB incident on a reflecting surface MN at angle of incidence i, with A striking the surface first while B is still travelling. …
- JKBOSE Class 12 Annual Regular Examination 2023Set ANNUAL5 marksQ.Stating the assumptions made and convention of signs used, derive the lens maker's formula in case of a double convex lens. OR Define fringe width. Derive an expression for fringe width in Young's double slit experiment of interference of light.
›Reveal solutionSolution
The lens maker's formula, 1/f = (n21-1)(1/R1 - 1/R2), is derived by applying refraction at each of the two spherical surfaces of a thin lens in turn. (OR: Fringe width beta = lambdaD/d is derived from the path-difference condition for constructive/destructive interference in Young's double-slit experiment.)
Derivation of Lens Maker's Formula (for a thin double convex lens):
Assumptions: (i) The lens is thin, so the two refracting surfaces are close enough that the lateral displacement of the ray inside the lens can be neglected. (ii) Only paraxial rays (making small angles with the principal axis) are considered. (iii) The medium on both sides of the lens is the same (say, refractive index n1), and the lens material has refractive index n2.
Sign convention: All distances are measured from the pole/optical centre of the surface; distances measured in the direction of the incident light are taken positive, against it negative. For a double convex lens, the first surface (facing the incident light) is convex towards the object, so its radius R1 is positive; the second surface curves the other way, so its radius R2 is negative.
Consider a point object O on the principal axis. Let the first surface (radius R1) refract the light from the object; treating this surface alone, the image I1 formed (a virtual, intermediate image) obeys the single-surface refraction formula:
n2/v1 - n1/u = (n2 - n1)/R1 ... (i)
where u is the object distance and v1 is the image distance for the first surface alone.
This intermediate image I1 now acts as a virtual object for the second surface (radius R2), which refracts the ray back into the surrounding medium n1, forming the final real image I at distance v:
n1/v - n2/v1 = (n1 - n2)/R2 ... (ii)
Adding equations (i) and (ii), the n2/v1 and -n2/v1 terms cancel:
n1/v - n1/u = (n2-n1)/R1 + (n1-n2)/R2 = (n2-n1)*(1/R1 - 1/R2).
Dividing throughout by n1:
1/v - 1/u = (n2/n1 - 1)(1/R1 - 1/R2) = (n21 - 1)(1/R1 - 1/R2), where n21 = n2/n1 is the refractive index of the lens material relative to the surrounding medium.
Now, if the object is placed at infinity (u tends to infinity), the rays refracted by the lens converge (for a convex lens) to the principal focus, so v = f (the focal length). Putting u = infinity, 1/u = 0:
1/f = (n21 - 1)*(1/R1 - 1/R2).
This is the Lens Maker's Formula. It relates the focal length f of a thin lens to the refractive index of its material (relative to the surrounding medium) and the radii of curvature of its two surfaces, and is used by lens manufacturers to design a lens of a required focal length. For a double convex lens (R1 positive, R2 negative), (1/R1 - 1/R2) is positive, so f comes out positive - confirming it is a converging lens.
…
- JKBOSE Class 12 Annual Regular Examination 2021Set SZ5 marksQ.Derive Lens-Maker's formula for convex lens. Write the necessary sign convention used. OR State Huygen's wave principles. Use them to prove laws of refraction of light.
›Reveal solutionSolution
The lens-maker's formula relates a thin lens's focal length to its refractive index and the radii of curvature of its two surfaces, derived by applying single-surface refraction twice.
Sign convention (Cartesian, as used in NCERT): All distances are measured from the optical centre of the lens. Distances measured in the direction of the incident light are taken as positive; distances measured against the direction of incident light are taken as negative. Heights measured upward from the principal axis are positive, downward are negative. For a convex lens, if the centre of curvature of a surface lies on the outgoing-light side, its radius R is positive; if on the incoming-light side, R is negative.
Derivation of lens-maker's formula:
Consider a thin convex lens of refractive index n2 placed in a medium of refractive index n1, with surfaces of radii R1 and R2. Let an object be at O on the principal axis.
Refraction at the first surface (radius R1) forms an image at I1 (treating the second surface as absent), using the single spherical refracting surface formula:
v1n2−un1=R1n2−n1
Refraction at the second surface (radius R2): the image I1 from the first surface now acts as a virtual object for the second surface, forming the final image at I (at distance v):
vn1−v1n2=R2n1−n2
Adding these two equations (the n2/v1 terms cancel):
vn1−un1=(n2−n1)(R11−R21)
Dividing throughout by n1:
v1−u1=(n1n2−1)(R11−R21)=(n21−1)(R11−R21)
When the object is at infinity (u→∞), the image forms at the focus, v=f, giving the general lens formula v1−u1=f1, so:
f1=(n21−1)(R11−R21)
where n21=n2/n1 is the refractive index of the lens material relative to the surrounding medium.
OR — Huygens' principle and laws of refraction:
Huygens' wave principle: Every point on a given wavefront (locus of points vibrating in phase) acts as a source of new secondary wavelets, which spread out in all directions with the speed of the wave in that medium. The new (secondary) wavefront at any later instant is the surface tangent (envelope) to all these secondary wavelets.
Derivation of Snell's law using Huygens' construction:
…
🎓Unlock everything free for 14 days
- ✓Full step-by-step solutions
- ✓Concept-first explanations
- ✓Methods, shortcuts & mistakes
- ✓PYQ mapping + timed mock tests
Full access for 14 days. No credit card required.