Q.A beam of light converges at a point P. Now a lens is placed in the path of the convergent beam 12 cm from P. At what point does the beam converge if the lens is
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🔒 Start your 14-day free trial to unlock the full solution →Concept understanding — Lens Maker's Formula
The Intuition: Why a Lens Bends Light
A lens works because light slows down when it enters glass. When a wavefront hits a curved surface at an angle, different parts of it slow down at different moments, and the wavefront bends. The stronger the curvature, the more it bends.
A lens has two surfaces. Each surface bends light by an amount that depends on its radius of curvature R and the refractive index n of the glass. The net bending — the focal length f — is the combined effect of both surfaces.
If you had a single spherical surface separating air from glass, its contribution to bending power is Rn−1. A lens has two such surfaces: light goes from air into glass at the first surface, then from glass back into air at the second. Because the two surfaces face opposite directions relative to the travelling light, their radii typically carry opposite signs.
This uses the New Cartesian Sign Convention (the one used in NCERT and CBSE): all distances are measured from the optical centre, and the direction the incident light travels in is taken as positive. So R is positive if the centre of curvature lies on the side the light is travelling towards (the outgoing side), and negative if it lies on the side the light is travelling from (the incident side).
The Precise Statement
For a thin lens (thickness negligible compared to the radii), the Lens Maker's Formula is:
f1=(n−1)(R11−R21)
where:
- f is the focal length of the lens (positive for converging, negative for diverging)
- n is the refractive index of the lens material relative to the surrounding medium (usually air)
- R1 is the radius of curvature of the first surface (the one light reaches first)
- R2 is the radius of curvature of the second surface
f1=(n−1)(R11−R21)
How to Apply It: A Worked Example
Take a biconvex lens made of glass (n=1.5) with both surfaces having the same radius of curvature magnitude, 20 cm.
Light travels left to right. The first surface bulges toward the incoming light, so its centre of curvature lies to the right of the surface — on the side the light is travelling towards. By the rule above, R1=+20 cm.
The second surface also bulges outward (away from the lens), so its centre of curvature lies to the left of that surface — on the side the light is travelling from. So R2=−20 cm.
Plug in:
f1=(1.5−1)(201−−201)=0.5×(201+201)=0.5×202=201
So f=+20 cm. Positive means converging — correct for a biconvex lens.
The most common mistake is getting the sign of R2 wrong. For a biconvex lens, R1 is positive and R2 is negative. For a biconcave lens, it's the reverse: R1 negative, R2 positive. Always sketch the lens and mark where each surface's centre of curvature actually sits.
Why the Formula Works (Brief Derivation) …
Concept: Refraction at a spherical surface / lens formula for a real object on the opposite side. Here the incident beam is converging toward P, so P acts as a virtual object for the lens (the rays would meet at P if the lens were absent).
Reasoning:
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For a lens, the Cartesian sign convention: distances measured against the incident light are negative. The incident beam is coming from the left and converging to P on the right. The lens is placed 12 cm before P, so the object distance u=+12 cm (positive because the object is virtual and lies on the right side).
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Lens formula: v1−u1=f1.
Substitute u=+12 cm.
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(a) Convex lens: f=+20 cm.
v1=201+121=603+5=608⇒v=7.5 cm. …
The key idea is to treat the converging beam as coming from a virtual object located 12 cm beyond the lens. Using the lens formula v1−u1=f1 with u=+12 cm (virtual object), we get: (a) for convex lens f=+20 cm, v=+7.5 cm (real image on the opposite side);
(b) for concave lens f=−16 cm, v=+48 cm (real image on the opposite side).
Why a virtual object?
When a beam of light is converging toward a point P, it means the rays are heading to meet at P without any lens. If you place a lens before P (i.e., in the path of the converging beam), the rays haven't yet reached P — they are still converging. From the lens's perspective, the rays appear to be coming from a point beyond the lens, on the other side. That point is a virtual object: the rays are real and converging toward it, but they never actually get there because the lens intercepts them.
For a converging beam incident on a lens, the object is virtual and its distance u is taken as positive in the Cartesian sign convention (since it lies on the opposite side of the lens from the incoming light).
Step-by-step solution
1. Set up the sign convention
We use the Cartesian sign convention (the standard for most Indian boards):
- Distances measured from the optical centre of the lens.
- Distances in the direction of incident light are positive.
- Distances opposite to incident light are negative.
- Focal length of convex lens: f=+20 cm.
- Focal length of concave lens: f=−16 cm.
The incident beam is converging toward P, which is 12 cm beyond the lens (on the other side). So the virtual object is at a distance u=+12 cm from the lens.
2. Lens formula
The lens formula is:
v1−u1=f1
where v is the image distance from the lens. A positive v means the image forms on the opposite side (real image), negative v means on the same side as the incident light (virtual image).
3. Part (a): Convex lens, f=+20 cm
Substitute u=+12 cm, f=+20 cm:
v1−121=201
v1=201+121=603+5=608=152
v=215=7.5 cm …
Method: Real Object / Virtual Object Approach for Lens Formula
This problem uses the lens formula with careful sign convention — the key insight is that when a converging beam meets a lens before reaching its focus, the point P acts as a virtual object for the lens.
Sign Convention (Cartesian)
- Distances measured from lens: positive in direction of incident light
- For a converging beam, the object lies beyond the lens → object distance u is positive
Step-by-step solution
Step 1: Identify object nature
The beam converges at P without the lens. With the lens placed 12 cm before P, the rays are heading toward P behind the lens.
→ P is a virtual object for the lens.
→ Object distance:
u=+12 cm
Step 2: Apply lens formula
v1−u1=f1
Step 3: Solve for each case
(a) Convex lens, f=+20 cm
v1−121=201
v1=201+121=603+5=608
v=+7.5 cm
Interpretation: Positive v means image forms on the same side as the incident light — i.e., 7.5 cm from lens toward P.
(b) Concave lens, f=−16 cm
v1−121=−161 …
Common Mistakes & How to Avoid Them
This is a classic "tricky" refraction problem because the light is converging before it hits the lens — it's not coming from a distant object. Here are the most common errors students make:
1. ✗ Assuming the object is at infinity
Mistake: Students see "convergent beam" and think u=∞, then blindly use 1/f=1/v.
Why it's wrong: The beam is already converging to point P. The lens intercepts this converging beam before it reaches P. The point P acts like a virtual object for the lens.
✓ How to avoid:
- Draw the ray diagram. The rays are heading toward P but hit the lens first.
- The object for the lens is the point where the rays would have met — that's P.
- Since the rays are converging toward P before the lens, P is a real object? No — careful: the rays are incident on the lens while converging. This makes P a virtual object (rays are converging to a point behind the lens from the lens's perspective).
2. ✗ Wrong sign convention for u
Mistake: Using u=+12 cm (positive) because "object is on the left."
Why it's wrong: In the Cartesian sign convention (used in most Indian boards):
- Light travels from left to right.
- For a real object, u is negative (object to the left of lens).
- Here, the rays are converging toward P which is on the right of the lens. The object (P) is on the right side of the lens — so u is positive.
✓ How to avoid:
- Always ask: "Where is the object relative to the lens?"
- If the object is on the right (opposite to incident light direction), u is positive.
- For this problem: u=+12 cm.
3. ✗ Using the lens formula incorrectly for virtual objects
Mistake: Plugging u=+12 into f1=v1−u1 without checking sign of f.
Why it's wrong: The lens formula is f1=v1−u1 (with sign convention). For a convex lens, f is positive; for concave, f is negative.
✓ How to avoid:
- Memorise:
- Convex lens: f>0
- Concave lens: f<0
- Then solve:
- (a) Convex: 201=v1−+121 → v1=201+121 → v=+7.5 cm
- (b) Concave: −161=v1−+121 → v1=−161+121 → v=+48 cm
4. ✗ Misinterpreting the sign of v
Mistake: Getting v=+7.5 cm and saying "image is 7.5 cm to the left of lens."
Why it's wrong: A positive v means the image is on the right side of the lens (the same side as the virtual object).
✓ How to avoid:
- Sign convention:
- v>0 → image on the right (real image for real object, but here it's a real image formed on the opposite side)
- v<0 → image on the left (virtual image) …
- JKBOSE Class 12 Annual Regular Examination 2026Set SZ5 marksQ.What is Lens Maker's formula? Derive an expression for Lens Maker's formula for a convex lens. OR State Huygen's Principle. Derive laws of reflection from Huygen's Principle.
›Reveal solutionSolution
The Lens Maker's formula, f1=(μ−1)(R11−R21), is derived by applying single-surface refraction twice, once at each face of the lens. (OR alternative: Huygens' Principle constructs wavefronts from secondary wavelets, and can be used to derive the laws of reflection geometrically.)
Part 1: Lens Maker's Formula
What it is. The Lens Maker's formula relates a lens's focal length f to the refractive index μ of its material (relative to the surrounding medium) and the radii of curvature R1, R2 of its two spherical surfaces — it tells a lens manufacturer what curvatures are needed to grind a lens of a desired focal length.
Derivation for a thin convex lens. Consider a thin lens with two refracting surfaces of radii R1 (first surface, light hits this first) and R2 (second surface), made of material of refractive index μ, surrounded by air (index 1). Let a point object O on the principal axis form an image after refraction at each surface in turn.
Step 1 — Refraction at the first surface (radius R1), treating it alone (ignoring the second surface for now), forming a virtual intermediate image I1 at distance v1:
v1μ−u1=R1μ−1
Step 2 — Refraction at the second surface (radius R2): the image I1 from step 1 now acts as the object for this second refraction (light going from the denser lens medium μ back into air, index 1), forming the final image I at distance v:
v1−v1μ=R21−μ
Step 3 — Add the two equations (the μ/v1 terms cancel):
v1−u1=(μ−1)(R11−R21)
Step 4 — Apply the lens definition. When the object is at infinity (u→∞), the image forms at the focus (v=f), so v1−u1→f1. Substituting:
f1=(μ−1)(R11−R21)
This is the Lens Maker's formula, and it also leads to the general thin lens formula v1−u1=f1.
OR: Huygens' Principle and the Laws of Reflection
Huygens' Principle. Every point on a given wavefront (a surface of constant phase) acts as a source of new secondary wavelets, which spread out in all directions with the speed of the wave in that medium. The new wavefront at any later time is given by the forward "envelope" (common tangent surface) of all these secondary wavelets.
Deriving the laws of reflection. Consider a plane wavefront AB incident on a reflecting surface MN at angle of incidence i, with A striking the surface first while B is still travelling. …
- JKBOSE Class 12 Annual Regular Examination 2023Set ANNUAL5 marksQ.Stating the assumptions made and convention of signs used, derive the lens maker's formula in case of a double convex lens. OR Define fringe width. Derive an expression for fringe width in Young's double slit experiment of interference of light.
›Reveal solutionSolution
The lens maker's formula, 1/f = (n21-1)(1/R1 - 1/R2), is derived by applying refraction at each of the two spherical surfaces of a thin lens in turn. (OR: Fringe width beta = lambdaD/d is derived from the path-difference condition for constructive/destructive interference in Young's double-slit experiment.)
Derivation of Lens Maker's Formula (for a thin double convex lens):
Assumptions: (i) The lens is thin, so the two refracting surfaces are close enough that the lateral displacement of the ray inside the lens can be neglected. (ii) Only paraxial rays (making small angles with the principal axis) are considered. (iii) The medium on both sides of the lens is the same (say, refractive index n1), and the lens material has refractive index n2.
Sign convention: All distances are measured from the pole/optical centre of the surface; distances measured in the direction of the incident light are taken positive, against it negative. For a double convex lens, the first surface (facing the incident light) is convex towards the object, so its radius R1 is positive; the second surface curves the other way, so its radius R2 is negative.
Consider a point object O on the principal axis. Let the first surface (radius R1) refract the light from the object; treating this surface alone, the image I1 formed (a virtual, intermediate image) obeys the single-surface refraction formula:
n2/v1 - n1/u = (n2 - n1)/R1 ... (i)
where u is the object distance and v1 is the image distance for the first surface alone.
This intermediate image I1 now acts as a virtual object for the second surface (radius R2), which refracts the ray back into the surrounding medium n1, forming the final real image I at distance v:
n1/v - n2/v1 = (n1 - n2)/R2 ... (ii)
Adding equations (i) and (ii), the n2/v1 and -n2/v1 terms cancel:
n1/v - n1/u = (n2-n1)/R1 + (n1-n2)/R2 = (n2-n1)*(1/R1 - 1/R2).
Dividing throughout by n1:
1/v - 1/u = (n2/n1 - 1)(1/R1 - 1/R2) = (n21 - 1)(1/R1 - 1/R2), where n21 = n2/n1 is the refractive index of the lens material relative to the surrounding medium.
Now, if the object is placed at infinity (u tends to infinity), the rays refracted by the lens converge (for a convex lens) to the principal focus, so v = f (the focal length). Putting u = infinity, 1/u = 0:
1/f = (n21 - 1)*(1/R1 - 1/R2).
This is the Lens Maker's Formula. It relates the focal length f of a thin lens to the refractive index of its material (relative to the surrounding medium) and the radii of curvature of its two surfaces, and is used by lens manufacturers to design a lens of a required focal length. For a double convex lens (R1 positive, R2 negative), (1/R1 - 1/R2) is positive, so f comes out positive - confirming it is a converging lens.
…
- JKBOSE Class 12 Annual Regular Examination 2021Set SZ5 marksQ.Derive Lens-Maker's formula for convex lens. Write the necessary sign convention used. OR State Huygen's wave principles. Use them to prove laws of refraction of light.
›Reveal solutionSolution
The lens-maker's formula relates a thin lens's focal length to its refractive index and the radii of curvature of its two surfaces, derived by applying single-surface refraction twice.
Sign convention (Cartesian, as used in NCERT): All distances are measured from the optical centre of the lens. Distances measured in the direction of the incident light are taken as positive; distances measured against the direction of incident light are taken as negative. Heights measured upward from the principal axis are positive, downward are negative. For a convex lens, if the centre of curvature of a surface lies on the outgoing-light side, its radius R is positive; if on the incoming-light side, R is negative.
Derivation of lens-maker's formula:
Consider a thin convex lens of refractive index n2 placed in a medium of refractive index n1, with surfaces of radii R1 and R2. Let an object be at O on the principal axis.
Refraction at the first surface (radius R1) forms an image at I1 (treating the second surface as absent), using the single spherical refracting surface formula:
v1n2−un1=R1n2−n1
Refraction at the second surface (radius R2): the image I1 from the first surface now acts as a virtual object for the second surface, forming the final image at I (at distance v):
vn1−v1n2=R2n1−n2
Adding these two equations (the n2/v1 terms cancel):
vn1−un1=(n2−n1)(R11−R21)
Dividing throughout by n1:
v1−u1=(n1n2−1)(R11−R21)=(n21−1)(R11−R21)
When the object is at infinity (u→∞), the image forms at the focus, v=f, giving the general lens formula v1−u1=f1, so:
f1=(n21−1)(R11−R21)
where n21=n2/n1 is the refractive index of the lens material relative to the surrounding medium.
OR — Huygens' principle and laws of refraction:
Huygens' wave principle: Every point on a given wavefront (locus of points vibrating in phase) acts as a source of new secondary wavelets, which spread out in all directions with the speed of the wave in that medium. The new (secondary) wavefront at any later instant is the surface tangent (envelope) to all these secondary wavelets.
Derivation of Snell's law using Huygens' construction:
…
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