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Q.Banking of roads helps to increase the limit of maximum safe speed of a vehicle at a curve.

(a) Draw the schematic diagram of a vehicle on a banked road and mark the various forces acting on it.
(2)
(b) Obtain an expression for the maximum safe speed of a vehicle at a banked road with frictional force. (3)
Kerala DhseKerala DHSE Plus One Board 2022Subjective· 5mImportance★★★★★
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Figure — The answer derives the banked-road result by resolving the normal reaction into components; fig-4-14 is the st
Figure — The answer derives the banked-road result by resolving the normal reaction into components; fig-4-14 is the st

On a flat road, only friction between the tyres and the road can supply the centripetal force needed to turn, which caps the safe speed at v_max = √(μsgr). Banking the road tilts the normal force so that a component of it points toward the centre of the curve as well, supplying (or supplementing) the centripetal force — this is why banking raises the maximum safe speed.

Setup

Consider a car of mass m going round a curve of radius r on a road banked at angle θ to the horizontal. Two forces act on the car (ignoring friction first, to find the ideal banking speed): the weight mg (vertically down) and the normal reaction N (perpendicular to the road surface, so tilted at angle θ from the vertical).

Resolve N into vertical and horizontal components

  • Vertical: N cosθ, which must balance the weight (the car neither sinks into nor lifts off the road):

    Ncos⁡θ=mg...(1)N\cos\theta = mg \quad \text{...(1)}

  • Horizontal: N sinθ, which points toward the centre of the circular path and must supply the required centripetal force mv²/r:

    Nsin⁡θ=mv2r...(2)N\sin\theta = \frac{mv^2}{r} \quad \text{...(2)}

Divide (2) by (1)

tan⁡θ=v2rg⇒v=rgtan⁡θ\tan\theta = \frac{v^2}{rg} \quad\Rightarrow\quad v = \sqrt{rg\tan\theta}

This is the speed at which the car can round the banked curve with no reliance on friction at all.

Why banking increases the maximum safe speed

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