Q.Complete the following reaction: phenol (C6H5OH) is treated with an aryldiazonium chloride, Ar–N2+ Cl−, in the presence of hydroxide ion (OH−, mildly alkaline medium). Give the product.
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Diazonium Salt Reactions – A First Look
Imagine you have a benzene ring, and you want to attach a new group — say a chlorine, a bromine, a cyano group, or even a hydroxyl — directly onto the ring. The benzene ring is stubborn; it doesn't easily let go of its hydrogen atoms for simple substitution. But there is a clever trick: first convert the ring into a diazonium salt, a highly reactive intermediate that will let you swap in almost any group you want.
That is the core idea. A diazonium salt is a temporary, energetic handle on the benzene ring that you can then replace with a wide variety of substituents. It is one of the most powerful tools in aromatic synthesis.
What is a Diazonium Salt?
A diazonium salt has the general formula Ar–N₂⁺ X⁻, where Ar is an aryl group (like phenyl, C₆H₅–), N₂⁺ is a diazonium cation (two nitrogen atoms triple-bonded, with a positive charge on the terminal nitrogen), and X⁻ is a counterion like chloride, bromide, or hydrogensulfate.
The key structural feature: the –N₂⁺ group is attached directly to the benzene ring. This group is unstable — it wants to leave as N₂ gas. That instability is exactly what makes it useful: when the N₂ leaves, the ring is left with a highly reactive carbocation-like intermediate that can be attacked by a nucleophile.
Diazonium salts are thermally unstable and can explode if dried. They are almost always prepared and used in cold solution (0–5 °C) without isolation.
How Do You Make One? (Diazotization)
You start with a primary aromatic amine (Ar–NH₂). Treat it with nitrous acid (HNO₂) at low temperature (0–5 °C). The reaction is:
Ar–NH2+NaNO2+2HCl0−5∘CAr–N2+Cl−+NaCl+2H2O
The nitrous acid is generated in situ from sodium nitrite and a mineral acid. The amine gets converted into the diazonium salt almost instantly. You must keep the solution cold; if it warms up, the diazonium salt decomposes and you get phenol and nitrogen gas.
Two Major Classes of Reactions
Once you have the diazonium salt in solution, you can do two fundamentally different things with it:
1. Substitution Reactions (N₂ leaves)
Here the –N₂⁺ group is replaced by another group. The nitrogen gas bubbles away, and the ring gets a new substituent. This is called dediazoniation. The leaving group is N₂, which is extremely stable, so the reaction is thermodynamically driven.
The most common substitutions:
| Reagent/Condition | Product | Name |
|---|---|---|
| CuCl / HCl, heat | Ar–Cl | Sandmeyer reaction |
| CuBr / HBr, heat | Ar–Br | Sandmeyer reaction |
| CuCN / KCN, heat | Ar–CN | Sandmeyer reaction |
| KI, heat | Ar–I | Direct substitution |
| H₂O, heat | Ar–OH | Hydrolysis |
| H₃PO₂ (hypophosphorous acid) | Ar–H | Reduction (replaces N₂ with H) |
| Cu₂O, Cu(NO₃)₂, H₂O | Ar–NO₂ | Replacement with nitro group |
The Sandmeyer reaction uses copper(I) halide or cyanide as a catalyst. The copper helps transfer the halide or cyanide to the ring. Without copper, the reaction is much slower or gives different products.
The mechanism for Sandmeyer: the diazonium salt accepts an electron from Cu⁺, forming an aryl radical, which then abstracts a halogen from CuX₂. The N₂ leaves as a gas.
2. Coupling Reactions (N₂ stays)
Here the diazonium salt keeps its N₂ group and attacks another aromatic ring (usually an activated one like phenol or aniline). The result is an azo compound with the general structure Ar–N=N–Ar'. These compounds are intensely coloured — many are used as dyes.
The reaction is an electrophilic aromatic substitution. The diazonium cation is a weak electrophile, so it only attacks rings that are strongly activated (with –OH, –NH₂, –NHR, –NR₂ groups). The coupling occurs at the para position if available; otherwise ortho.
Example: coupling with phenol in alkaline medium:
C6H5–N2+Cl−+C6H5–OHNaOH, 0–5∘CC6H5–N=N–C6H4–OH (p-hydroxyazobenzene, orange dye)
Coupling requires the coupling component (phenol or aniline) to be in its reactive form: phenol is used in alkaline solution (phenoxide ion is more activating), aniline is used in slightly acidic or neutral solution (to avoid protonation of the amino group).
Why Are Diazonium Salts So Versatile? …
This is an azo coupling. The aryldiazonium ion is a weak electrophile that attacks the electron-rich phenol ring, preferentially at the para position, to give a coloured azo compound. …
An aryldiazonium salt couples with phenol in mild alkali by electrophilic aromatic substitution at the position para to –OH, giving a p-hydroxyazobenzene (an orange azo dye).
Concept – Azo coupling
The diazonium cation Ar–N2+ is a weak electrophile. It reacts only with strongly activated rings such as phenols and aromatic amines. In mild alkali the phenol is converted to the phenoxide ion (–O−), which is even more activating, so coupling occurs readily.
Regiochemistry
The –OH (or –O−) group directs the incoming diazonium electrophile ortho/para; the para position is preferred (less steric hindrance). The nitrogen of the diazonium becomes the –N=N– (azo) link.
Reaction …
Method: Azo Coupling of a Diazonium Salt with an Activated Arene
Core Concept
An aryldiazonium ion is a weak electrophile that can only attack very electron-rich (strongly activated) rings such as phenols or aromatic amines; in mild alkali the substrate becomes even more activated, and coupling proceeds by ordinary electrophilic aromatic substitution to give a coloured azo compound.
Steps
- Identify the electrophile: Ar-N2+ (weak, because the positive charge is delocalised over the N=N system).
- Identify the substrate and check it is strongly activating (phenol/aniline-type ring) - an ordinary benzene ring is too unreactive to couple.
- Note the effect of the mild alkaline medium: phenol (C6H5OH) is converted to the more nucleophilic phenoxide ion (C6H5O-), which activates the ring further and drives the coupling.
- Apply the directing rule of -OH/-O-: an ortho/para director; predict attack mainly at the position para to -OH (less hindered than ortho). …
- KEAM 2025Set pha-2025-0424F4 marksMCQQ.Aryl fluorides are prepared from diazonium salts using (A) NaF (B) KF (C) BF3 (D) AlF3 (E) HBF4
›Reveal solutionSolution
Diazonium salt + fluoroboric acid (HBF4) → diazonium tetrafluoroborate Δ aryl fluoride (ArF) + N2 + BF3. This is the Balz–Schiemann reaction.
Reaction:
ArN2+Cl−+HBF4→ArN2+BF4−ΔArF+N2+BF3 …
- KEAM 2025Set pha-2025-0424A4 marksMCQQ.Nitrobenzene is treated with Sn/HCl to give a compound (X) which on treatment with NaNO2 and HCl at 278 K gives compound (Y). When the compound (Y) is treated with Cu/HBr , compound 'Z' is obtained. The compound 'Z' is (A) Benzene (B) Benzene diazonium bromide (C) Phenol (D) Bromobenzene (E) Chlorobenzene
›Reveal solutionSolution
C6H5NO2Sn/HClC6H5NH2 (X) NaNO2/HCl,278KC6H5N2+Cl− (Y) Cu/HBrC6H5Br (Z). …
- KEAM 2025Set pha-2025-0429F4 marksMCQQ.Benzene diazonium chloride on treatment with reagent 'X' gives iodobenzene. The regeant 'X' is (A) Cu2I2 (B) AgI (C) I2 (D) HI (E) KI
›Reveal solutionSolution
Iodobenzene is made from benzene diazonium chloride simply by warming it with KI — no cuprous salt is needed, unlike for Cl/Br.
Aryl iodides are prepared by treating an arenediazonium salt with potassium iodide:
C6H5N2+Cl−+KI→C6H5I+N2+KCl. …
- KEAM 2024Set eng-2024-06064 marksMCQQ.A reagent that can be used to reduce benzene diazonium chloride to benzene is (A) ethanol (B) methanol (C) methanoic acid (D) acetone (E) phosphorous acid
›Reveal solutionSolution
The diazonium −N2+ group can be reduced/replaced by hydrogen using ethanol (or hypophosphorous acid): C6H5N2+Cl−+C2H5OH→C6H6+CH3CHO+N2+HCl.
Among the options, ethanol is the standard NCERT reagent that reduces benzenediazonium chloride to benzene, liberating nitrogen while being itself oxidised to acetaldehyde. Methanol, methanoic acid, acetone and phosphoro …
- KEAM 2024Set eng-2024-06084 marksMCQQ.When benzene diazonium fluoroborate is heated with aqueous sodium nitrite solution in the presence of copper, the product formed is (A) fluorobenzene (B) benzene (C) aniline (D) nitrobenzene (E) phenol
›Reveal solutionSolution
This is the diazonium route to nitroarenes: C6H5N2+BF4− with NaNO2/Cu gives nitrobenzene (−N2+ replaced by −NO2).
Benzene diazonium fluoroborate on warming with aqueous sodium nitrite in the presence of copper powder undergoes substitution of the diazonium group by a nitro group:
C6H5N2+BF4−NaNO2CuC6H5NO2+N2+NaBF4 …
- KEAM 2024Set pha-2024-06104 marksMCQQ.Gatterman reaction is used to convert benzene diazonium chloride to (A) benzene (B) nitrobenzene (C) phenetole (D) phenol (E) chlorobenzene
›Reveal solutionSolution
Benzene diazonium chloride + Cu/HCl → chlorobenzene (Gattermann).
In the Gattermann reaction, a benzene diazonium salt is treated with copper powder and the corresponding halogen acid (HCl/HBr). Benzene diazonium chloride with Cu/HCl gives chlorobenzene (with loss of N2). It is the copp …
- KEAM 2022Set eng-2022-P1-A14 marksMCQQ.The product formed, when benzene diazonium fluoroborate is heated with aqueous sodium nitrite solution in the presence of copper is (A) fluorobenzene (B) benzene (C) phenol (D) p-nitrophenol (E) nitrobenzene
›Reveal solutionSolution
Heating benzene diazonium fluoroborate with aqueous sodium nitrite and copper gives nitrobenzene.
Concept and Intuition
This is a variant of the Sandmeyer/Balz reaction: the diazonium salt, in the presence of Cu and nitrite ion, has its -N2+ group replaced by -NO2, converting the arene to a nitroarene.
Step-by-Step Solution
- C6H5N2+BF4- provides the aryl group with a displaceable diazonium.
- With NaNO2 and Cu, the nitrite ion substitutes for N2. …
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