Q.Assertion: Presence of a nitro group at ortho or para position increases the reactivity of haloarenes towards nucleophilic substitution.
Reason: Nitro group, being an electron withdrawing group decreases the electron density over the benzene ring.
🔒You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.
🔒 Start your 14-day free trial to unlock the full solution →Concept understanding — Inductive Effect on Acidity
Inductive Effect on Acidity – From Intuition to Precision
Imagine you are holding a rope tied to a heavy box. If you pull the rope, the box moves toward you. Now imagine the rope is made of rubber bands — the pull still reaches the box, but it gets weaker the farther away you are. That is exactly how the inductive effect works inside a molecule.
The Core Intuition
An acid donates a proton (H+). After it does, the remaining part (the conjugate base) carries a negative charge. The stability of that negative charge determines how willing the molecule is to give up the proton. More stable conjugate base → stronger acid.
Now, some atoms or groups are electron-withdrawing — they pull electron density toward themselves through the sigma bonds. If such a group is attached near the acidic proton, it pulls some electron density away from the negative charge on the conjugate base. That spreads out (delocalises) the negative charge, making the conjugate base more stable. The acid becomes stronger.
Conversely, electron-donating groups push electron density toward the negative charge, concentrating it and making the conjugate base less stable. The acid becomes weaker.
The inductive effect operates through sigma bonds only. It does not involve pi bonds or resonance. It is a permanent, through-bond polarisation.
The Precise Statement
Inductive effect on acidity: The acidity of a compound increases with the presence of electron-withdrawing groups (EWGs) near the acidic site, and decreases with electron-donating groups (EDGs). The effect is strongest when the group is closest to the acidic proton, and diminishes rapidly with distance.
Mathematically, for a series of substituted carboxylic acids:
R-COOHwhere R = substituent
The acid dissociation constant Ka changes as:
- If R is electron-withdrawing (e.g., −Cl, −NO2, −CF3): Ka increases → stronger acid.
- If R is electron-donating (e.g., −CH3, −C2H5): Ka decreases → weaker acid.
Why Distance Matters
The inductive effect falls off with distance because sigma bonds are localised. Each bond attenuates the effect by roughly a factor of 2–3. For example, compare:
| Compound | pKa | Explanation |
|---|---|---|
| CH3COOH | 4.76 | Reference (no EWG) |
| ClCH2COOH | 2.86 | Cl withdraws through one bond |
| Cl2CHCOOH | 1.29 | Two Cl atoms, stronger withdrawal |
| Cl3CCOOH | 0.65 | Three Cl atoms, strongest withdrawal |
| CH3CH2COOH | 4.87 | Ethyl group is electron-donating (slightly weaker acid) |
Notice: ClCH2COOH is about 100 times stronger than acetic acid (ΔpKa≈1.9). But if the Cl is moved further away:
| Compound | pKa |
|---|---|
| ClCH2CH2COOH | 4.08 |
| ClCH2CH2CH2COOH | 4.52 |
The effect fades as the chlorine moves farther from the carboxyl group. …
Why this formula?
Inductive Effect on Acidity: Why It Works
The inductive effect is a through-bond electron displacement caused by differences in electronegativity. When we ask why it affects acidity, we must first understand what acidity means at the molecular level.
The Core Idea: Stabilising the Conjugate Base
Acidity is governed by the equilibrium:
HA⇌H++A−
The stronger the acid, the more it favours the right side. This happens when the conjugate base A− is more stable. The inductive effect directly influences this stability.
Why Electron-Withdrawing Groups (EWG) Increase Acidity
Consider a carboxylic acid with an electronegative atom (like Cl) attached to the carbon chain:
Cl−CH2−COOH
- The inductive pull: The Cl atom is more electronegative than carbon. It pulls electron density toward itself through the sigma bonds.
- Effect on the O–H bond: This electron withdrawal travels along the carbon chain, reducing electron density around the O–H bond. The bond becomes more polarised, making the H⁺ easier to remove.
- Stabilising the conjugate base: After losing H⁺, the negative charge on the carboxylate ion (RCOO−) is delocalised by resonance. But the inductive effect further stabilises this negative charge by pulling electron density away from the oxygen atoms. This makes the conjugate base less reactive (more stable), shifting equilibrium toward dissociation.
Key insight: The inductive effect doesn't just weaken the O–H bond — it stabilises the anion that forms after deprotonation.
The Quantitative Relationship: Hammett Equation
For substituted benzoic acids, the effect is quantified by the Hammett equation:
log(Ka0Ka)=σρ
Where:
- Ka = acid dissociation constant of substituted acid
- Ka0 = acid dissociation constant of unsubstituted benzoic acid
- σ = substituent constant (measures inductive + resonance effect)
- ρ = reaction constant (sensitivity of the reaction to substituent effects)
Why This Formula Holds
The derivation comes from linear free-energy relationships:
- Free energy change: For any acid dissociation:
ΔG∘=−RTlnKa
- Effect of substituent: A substituent changes ΔG∘ by an amount proportional to its electronic effect:
Δ(ΔG∘)=−RTln(Ka0Ka)
-
Separability assumption: The total effect of a substituent on any reaction can be factored into:
- A substituent-specific term (σ) — how strongly it pulls/pushes electrons
- A reaction-specific term (ρ) — how sensitive the reaction is to electronic effects
-
Empirical validation: Hammett found that for meta and para substituted benzoic acids, plotting log(Ka/Ka0) against σ gives a straight line. This confirms the additive nature of inductive effects.
The Inductive Effect Constant (σI) …
The key idea is that a nitro group activates the ring toward nucleophilic substitution by withdrawing electron density through both inductive and resonance effects, making the carbon attached to the halogen more electrophilic.
Step 1: In nucleophilic aromatic substitution (SNAr), the rate depends on how easily the nucleophile can attack the carbon bearing the halogen. An electron-withdrawing group (EWG) at the ortho or para position stabilises the intermediate Meisenheimer complex by delocalising its negative charge.
Step 2: The nitro group is a strong EWG — it withdraws electrons inductively and also by resonance (through its −M effect). This reduces electron density on the ring, especially at ortho and para positions, making the haloarene more susceptible to attack by a nucleophile. …
A nitro group at the ortho or para position genuinely does increase the reactivity of a haloarene towards nucleophilic substitution, and it does so precisely because it is a strong electron-withdrawing group that pulls electron density off the ring — that withdrawal is what stabilises the negatively-charged Meisenheimer intermediate the reaction goes through. Both statements are correct, and the reason correctly explains the assertion. The correct option is (i).
Why haloarenes are normally slow to undergo nucleophilic substitution
In an ordinary haloarene like chlorobenzene, the ring is electron-rich (helped along by the halogen's own lone-pair donation into the ring), so an incoming nucleophile finds the ring carbon unattractive to attack. Harsh conditions are usually needed.
What a nitro group changes
A nitro group is a powerful electron-withdrawing group, both through induction and through resonance. As the diagram shows, the ring's own π electrons can shift toward the nitro group, leaving a formal positive charge on the ring carbon and extra negative charge on a nitro oxygen. This withdrawal lowers the electron density on the ring overall — the exact statement the reason makes.
Why that withdrawal is the correct explanation …
Method: Resonance and Inductive Effect Analysis for Nucleophilic Aromatic Substitution
Step 1 – Identify the reaction type
The question deals with nucleophilic aromatic substitution (SNAr) in haloarenes.
In SNAr, the rate depends on how easily the leaving group (halogen) can be displaced by a nucleophile.
Step 2 – Role of the nitro group
A nitro group (−NO2) is a strong electron-withdrawing group by both inductive effect and resonance effect.
- Inductive effect: pulls electron density through sigma bonds.
- Resonance effect: delocalizes the negative charge from the ring into the nitro group, especially at ortho and para positions.
Step 3 – Effect on reactivity
When a nitro group is at ortho or para position relative to the halogen:
- It stabilizes the Meisenheimer complex (the negatively charged intermediate) by delocalizing the negative charge.
- This lowers the activation energy for the nucleophilic attack.
- Hence, reactivity increases.
Step 4 – Evaluate the Assertion and Reason
- Assertion: Correct — ortho/para nitro groups increase reactivity in SNAr.
- Reason: Correct — nitro group is electron-withdrawing and decreases electron density on the ring.
- But: The reason is incomplete — it only mentions the inductive effect. The key explanation is the resonance stabilization of the intermediate, not just the decrease in electron density. So, the reason is not the correct explanation of the assertion.
Step 5 - Final answer …
Here are the common mistakes students make on this exact question, along with how to avoid each one.
Mistake 1: Confusing "Reactivity" with "Acidity"
- The Error: Students see "nitro group" and "electron withdrawing" and immediately think of acidity (e.g., comparing pKa of phenols or carboxylic acids).
- Why It's Wrong: This question is about nucleophilic substitution in haloarenes, not about acid strength. The electron withdrawal here affects the rate of SNAr (nucleophilic aromatic substitution), not proton donation.
- How to Avoid: Always check the context of the question. If it mentions "haloarenes" and "nucleophilic substitution," think about how easily a nucleophile can attack the ring carbon bearing the halogen, and how well the resulting negatively-charged intermediate (the Meisenheimer complex) is stabilised.
Mistake 2: Thinking the Assertion Is False
- The Error: Some students think the assertion is false because they recall that nitrobenzene is less reactive than benzene in electrophilic substitution, and assume the same logic applies here.
- Why It's Wrong: That's a different reaction type. For nucleophilic substitution, an electron-withdrawing group like nitro at ortho/para increases reactivity — it's the opposite trend from electrophilic substitution.
- How to Avoid: Clearly separate electrophilic vs nucleophilic substitution in your mind:
- Electrophilic substitution: Nitro group deactivates the ring (electrophiles want an electron-rich ring).
- Nucleophilic substitution: Nitro group activates the ring at ortho/para (nucleophiles want an electron-poor, attackable ring carbon).
Mistake 3: Dismissing the Reason as "Too Vague" and Marking It False
- The Error: Students feel the reason ("decreases electron density over the ring") is incomplete — since it doesn't explicitly mention the Meisenheimer complex or resonance — and conclude it must be the "wrong statement," picking (iii) or (iv). …
- KEAM 2026Set eng-2026-04174 marksMCQQ.Which of the following carboxylic acid has the highest pKa value? (A) O2N-CH2-COOH (B) F-CH2-COOH (C) HCOOH (D) CN-CH2COOH (E) Cl-CH2COOH
›Reveal solutionSolution
Among the choices, HCOOH lacks any strong electron-withdrawing α-substituent, so its conjugate base is least stabilised — it is the weakest acid and thus has the highest pKa.
Acidity of a carboxylic acid rises (i.e. pKa falls) when an electron-withdrawing group near the −COOH stabilises the carboxylate anion.
- O2N−CH2COOH: strong −I nitro, very low pKa. …
- KEAM 2026Set eng-2026-04224 marksMCQQ.The decreasing order of acid strength of the following is (A) FCH2COOH>NCCH2COOH>NO2CH2COOH>ClCH2COOH (B) CNCH2COOH>O2NCH2COOH>FCH2COOH>ClCH2COOH (C) NO2CH2COOH>NCCH2COOH>FCH2COOH>ClCH2COOH (D) NO2CH2COOH>FCH2COOH>NCCH2COOH>ClCH2COOH (E) ClCH2COOH>FCH2COOH>NCCH2COOH>NO2CH2COOH
›Reveal solutionSolution
The stronger the electron-withdrawing substituent, the more acidic the acetic acid: NO2>CN>F>Cl, giving O2NCH2COOH>NCCH2COOH>FCH2COOH>ClCH2COOH. …
- KEAM 2025Set eng-2025-04254 marksMCQQ.Which of the following acid is highly acidic? (A) Fluoroacetic acid (B) Formic acid (C) Dichloroacetic acid (D) Benzoic acid (E) Acetic acid.
›Reveal solutionSolution
Acid strength increases with electron-withdrawing substituents that stabilise the conjugate base. Two chlorines in dichloroacetic acid (pKa≈1.3) make it the most acidic here.
Comparing approximate pKa values (lower = more acidic):
- Dichloroacetic acid: ~1.3 (two −I Cl atoms) — strongest.
- Fluoroacetic acid: ~2.6.
- Formic acid: ~3.75.
- Benzoic acid: ~4.2.
- Acetic acid: ~4.76. …
- KEAM 2025Set eng-2025-04294 marksMCQQ.Which of the following is the strongest acid? (A) FCH2COOH (B) CF3COOH (C) NC-CH2COOH (D) Br-CH2COOH (E) CH3COOH
›Reveal solutionSolution
Acid strength rises with the electron-withdrawing power near the -COOH. Three fluorines in CF3COOH give the strongest -I effect and the most stabilised conjugate base, so it is the strongest acid.
Substituted acetic acids become stronger as the electron-withdrawing (–I) effect of the substituent increases, because a more stabilised carboxylate anion means a more readily released proton.
- CH3COOH (E): electron-donating methyl, weakest acid. …
- KEAM 2025Set pha-2025-0424F4 marksMCQQ.Which of the following is the weakest acid? (A) FCH2COOH (B) NC−CH2COOH (C) Cl3C−COOH (D) O2N−CH2COOH (E) Cl2CHCOOH
›Reveal solutionSolution
Acidity rises with electron-withdrawing power near the –COOH. Comparing the groups, mono-fluoro on one α-C (FCH2COOH, pKa≈2.6) is the least acid-strengthening, so it is the weakest acid.
Comparison (approximate pKa):
- Cl3C−COOH (trichloroacetic): ≈0.7 — three Cl directly on the carbonyl carbon, strongest.
- Cl2CH−COOH (dichloroacetic): ≈1.3.
- O2N−CH2COOH (nitroacetic): ≈1.7.
- NC−CH2COOH (cyanoacetic): ≈2.5. …
- KEAM 2024Set eng-2024-06054 marksMCQQ.Which of the following carboxylic acid has the highest pKa? (A) ethanoic acid (B) chloroethanoic acid (C) fluoroethanoic acid (D) dichloroethanoic acid (E) triflouroethanoic acid
›Reveal solutionSolution
Electron-withdrawing halogens stabilise the carboxylate and lower pKa; unsubstituted ethanoic acid, having none, has the highest pKa.
Acid strength increases (pKa decreases) with the number and electronegativity of α-halogen substituents, which stabilise the conjugate base by the −I effect. The order of increasing acidity is roughly: …
- KEAM 2024Set eng-2024-06064 marksMCQQ.The order of decreasing acid strength of carboxylic acids is (A) FCH2COOH>ClCH2COOH>NO2CH2COOH>CNCH2COOH (B) CNCH2COOH>FCH2COOH>NO2CH2COOH>ClCH2COOH (C) NO2CH2COOH>FCH2COOH>ClCH2COOH>CNCH2COOH (D) FCH2COOH>NO2CH2COOH>ClCH2COOH>CNCH2COOH (E) NO2CH2COOH>CNCH2COOH>FCH2COOH>ClCH2COOH
›Reveal solutionSolution
Acidity follows the electron-withdrawing (−I) strength: NO2>CN>F>Cl, matching the pKa order.
Electron-withdrawing substituents on the α-carbon stabilise the carboxylate and raise acidity. The experimental pKa values are: nitroacetic ≈1.68, cyanoacetic ≈2.47, fluoroacetic ≈2.59, chloroacetic ≈2.87. Lower …
- KEAM 2024Set eng-2024-06094 marksMCQQ.The increasing order of acid strength of the following carboxylic acids is(i) (CH3)3C-COOH(ii) (CH3)2CH-COOH(iii) CH3CH2COOH (A)(ii) <(i) <(iii) (B)(i) <(iii) <(ii) (C)(ii) <(iii) <(i) (D)(iii) <(ii) <(i) (E)(i) <(ii) < (iii)
›Reveal solutionSolution
Electron-donating alkyl groups destabilise the carboxylate; more branching = weaker acid.
The acids are (i) (CH3)3C-COOH (tert-butyl, three methyls), (ii) (CH3)2CH-COOH (isopropyl, two methyls), (iii) CH3CH2-COOH (ethyl, one methyl on the α-carbon side). Electron-donating (+I) alkyl groups intensify the negative charge on the carboxylate anion, destabilising it and …
- KEAM 2021Set eng-2021-P1-A14 marksMCQQ.The increasing order of acid strength of the following carboxylic acids is (A) ClCH2-CH2-COOH<ClCH2COOH<NC-CH2COOH<CHCl2COOH (B) ClCH2-COOH<NC-CH2COOH<ClCH2CH2COOH<CHCl2COOH (C) ClCH2-CH2-COOH<CHCl2-COOH<ClCH2-COOH<NC-CH2-COOH (D) NC-CH2-COOH<Cl-CH2COOH<CH-Cl2COOH<Cl-CH2CH2COOH (E) ClCH2CH2-COOH<CHCl2COOH<ClCH2COOH<NC-CH2COOH
›Reveal solutionSolution
Acidity increases: ClCH2CH2COOH<ClCH2COOH<NCCH2COOH<CHCl2COOH.
Concept and Intuition
Electron-withdrawing groups stabilise the carboxylate anion (–I effect), increasing acidity; the effect is stronger when the group is closer to –COOH and when there are more/stronger withdrawing groups.
Step-by-Step Solution
- ClCH2CH2COOH: Cl is one carbon farther (β to COOH), weak effect ⇒ pKa ≈ 4.0 (weakest acid).
- ClCH2COOH: one α-Cl ⇒ pKa ≈ 2.87.
- NCCH2COOH: –CN is a stronger –I group than Cl ⇒ pKa ≈ 2.47.
- CHCl2COOH: two α-Cl ⇒ pKa ≈ 1.29 (strongest). …
🎓Unlock everything free for 14 days
- ✓Full step-by-step solutions
- ✓Concept-first explanations
- ✓Methods, shortcuts & mistakes
- ✓PYQ mapping + timed mock tests
Full access for 14 days. No credit card required.