Skip to content
Exercises · Q16

Q.Find the slope of the line passing through the points (−1,2)(-1, 2) and (3,−6)(3, -6).

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
10% · 2/21 Questions
✓ Free question

Using m=y2−y1x2−x1m = \dfrac{y_2 - y_1}{x_2 - x_1} with (x1,y1)=(−1,2)(x_1, y_1) = (-1, 2) and (x2,y2)=(3,−6)(x_2, y_2) = (3, -6):

m=−6−23−(−1)=−83+1=−84=−2m = \dfrac{-6 - 2}{3 - (-1)} = \dfrac{-8}{3 + 1} = \dfrac{-8}{4} = -2

Check (independent). Reversing the order: 2−(−6)−1−3=8−4=−2\dfrac{2 - (-6)}{-1 - 3} = \dfrac{8}{-4} = -2, the same value. The negative slope also makes sense: as xx increases from −1-1 to 33, yy decreases from 22 to −6-6, so the line falls.

✓Final answer

Slope m=−2m = -2.

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests
Start 14-day free trial →See Plans & Pricing →

Full access for 14 days. No credit card required.

←Previous questionQ15 — Find the equation of the locus of a point which is equidistant from th…→Next questionQ17 — Find the equation of the line having x-intercept 2 and y-intercept -5.