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Exercises · Q18

Q.Find the equation of the line passing through (4,5)(4, 5) and parallel to the line 2x−y+3=02x - y + 3 = 0.

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A line parallel to 2x−y+3=02x - y + 3 = 0 has the same coefficients of xx and yy, so write it as

2x−y=k2x - y = k

Since it passes through (4,5)(4, 5):

2(4)−5=k ⇒ 8−5=k ⇒ k=32(4) - 5 = k \ \Rightarrow\ 8 - 5 = k \ \Rightarrow\ k = 3

Hence the line is 2x−y−3=02x - y - 3 = 0. …

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