Q.State the octet rule. Explain its inadequacies with respect to
Step 1. State the octet rule. During bond formation, an atom loses, gains, or shares electrons so its outermost (valence) shell ends up with eight electrons, matching the nearest noble gas's stable configuration (H and Li are the acknowledged exceptions, stable with a two-electron duplet).
Step 2(a). Incomplete octet. Some central atoms are stable with FEWER than eight electrons around them because they simply do not have enough valence electrons to share even after bonding: Li in LiCl has only 2 electrons around it, Be in BeCl2 has only 4 (two single bonds, no lone pair), and B in BF3 has only 6 (three single bonds, no lone pair) — all three molecules are perfectly stable despite the incomplete octet.
Step 2(b). Expanded octet. Other central atoms end up with MORE than eight electrons around them, made possible by their access to low-lying d orbitals that can house the extra shared pairs: S in SF6 has 12 electrons around it (6 single S-F bonds), P in PCl5 has 10 (5 single P-Cl bonds), and S in H2SO4 also has 12. (By contrast, S in SCl2 obeys the ordinary octet rule with only 8 electrons, showing expanded octets are a property of the specific compound, not the element itself.)
Octet rule: 8 valence electrons (ns2np6), except H/Li (duplet). Incomplete octet examples: LiCl, BeCl2, BF3. Expanded octet examples: SF6, PCl5, H2SO4.
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