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Draw · Q7

Q.Lewis dot diagrams for the following:

(a) Hydrogen (H2)
(b) Water (H2O)
(c) Carbon dioxide (CO2)
(d) Methane (CH4)
(e) Lithium Fluoride (LiF)
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✓ Free question

Step 1. H2 (2 valence electrons total). Each H contributes 1 electron; sharing gives one pair, H:H or H–H, with each H reaching helium's duplet.

Step 2. H2O (8 valence electrons: O's 6 + 2×H's 1). O is central; two O–H single bonds use 4 electrons, leaving O with 2 lone pairs (4 electrons); each H reaches a duplet, O reaches an octet.

Step 3. CO2 (16 valence electrons: C's 4 + 2×O's 6). C is central; a single-bond skeleton leaves C's octet short, so both C–O bonds become double bonds, O=C=O, each O keeping 2 lone pairs; C and both O reach octets.

Step 4. CH4 (8 valence electrons: C's 4 + 4×H's 1). C is central with four single C–H bonds, using all 8 electrons; C reaches an octet, each H a duplet.

Step 5. LiF. Li (1 valence electron) transfers it entirely to F (7 valence electrons); this is an IONIC bond, not a shared pair, giving Li⊕ (duplet, like He) and [:F:]⊖ (octet, like Ne) held by electrostatic attraction, not a Lewis dot 'sharing' diagram.

✓Final answer

H2: H–H · H2O: H–O–H with 2 lone pairs on O · CO2: O=C=O · CH4: 4 single C–H bonds · LiF: Li⊕[:F:]⊖ (ionic)

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