Q.Lewis electron dot structures of:
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Start your 14-day free trial to unlock the full solution →Step 1. HF (8 valence electrons: H's 1 + F's 7). One H-F single bond; F carries 3 lone pairs to complete its octet, H reaches a duplet.
Step 2. C2H6/ethane (14 valence electrons: 2×C's 4 + 6×H's 1). One C-C single bond; each carbon also singly bonded to 3 H atoms; every C reaches an octet, every H a duplet; no lone pairs anywhere (all electrons used in bonds).
Step 3. C2H4/ethene (12 valence electrons). One C=C double bond plus two C-H single bonds per carbon (4 C-H total); every C reaches an octet, every H a duplet.
Step 4. CF3Cl. C is central (least electronegative), singly bonded to three F atoms and one Cl atom; each halogen carries 3 lone pairs to complete its octet, C reaches an octet with 4 single bonds, no lone pair on C. …
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