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Exercise · Q7

Q.Explain the following:
Hydrogen shows similarity with alkali metals as well as halogens.

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Step 1. Resemblance to alkali metals. Hydrogen has one valence electron (1s¹), just like the alkali metals' ns¹. Both hydrogen and the alkali metals react with a halogen X2 to form a compound of general formula HX / MX respectively (H2 + Cl2 → 2HCl; 2Na + Cl2 → 2NaCl) — both are monovalent, electropositive with respect to the halogen.

Step 2. Resemblance to halogens. Halogens have configuration ns²np⁵, one electron short of the next noble gas; hydrogen's 1s¹ is likewise one electron short of helium's 1s². So, like a halogen gaining an electron to form X⁻, hydrogen can gain an electron to form the hydride ion H⁻ (e.g. in NaH), showing halogen-like behaviour.

Step 3. Conclusion. Because hydrogen can either lose its one electron (alkali-metal-like) or gain one electron (halogen-like), it genuinely straddles both families, which is why it is placed separately, above group 1, rather than fully inside either group.

✓Final answer

Hydrogen resembles alkali metals because both are monovalent and form 1:1 compounds with halogens (HX and MX) by losing/sharing one electron; it resembles halogens because, like them, gaining one electron completes hydrogen's shell to the next noble gas (He), so it can also gain an electron to form H⁻, similar to a halogen forming X⁻.

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