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Solve the following problems · Q33

Q.Find the percentage composition of constituent green vitriol crystals (FeSO4.7H2O). Also find out the mass of iron and the water of crystallisation in 4.54 kg of the crystals. (At. mass : Fe = 56; S = 32; O = 16) (Ans.: mass of Fe = 0.915 kg, mass of 7H2O = 2.058 kg)

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Step 1. Molar mass of FeSO4.7H2O =56+32+4(16)+7(18)=56+32+64+126=278= 56 + 32 + 4(16) + 7(18) = 56+32+64+126 = 278 g/mol.

Step 2. %Fe =56/278×100=20.14%= 56/278\times100 = 20.14\%; %S =32/278×100=11.51%= 32/278\times100 = 11.51\%; %O (in the sulfate) =64/278×100=23.02%= 64/278\times100 = 23.02\%; %water of crystallisation =126/278×100=45.32%= 126/278\times100 = 45.32\% (sums to ≈99.99%). …

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