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Solve the following problems · Q39

Q.A compound on analysis gave the following percentage composition by mass : H = 9.09; O = 36.36; C = 54.55. Mol mass of compound is 88. Find its molecular formula.

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Step 1. Moles: H =9.09/1=9.09= 9.09/1 = 9.09; O =36.36/16=2.2725= 36.36/16 = 2.2725; C =54.55/12=4.546= 54.55/12 = 4.546.

Step 2. Divide by the smallest (O, 2.2725): H =4.00= 4.00; O =1.00= 1.00; C =2.00= 2.00, giving empirical formula C2H4O. …

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