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Solve the following problems · Q35

Q.A substance, on analysis, gave the following percent composition: Na = 43.4 %, C = 11.3 % and O = 45.3 %. Calculate the empirical formula. (At. mass Na = 23 u, C = 12 u, O = 16 u). (Ans.: Na2CO3)

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Step 1. Moles: Na =43.4/23=1.887= 43.4/23 = 1.887; C =11.3/12=0.9417= 11.3/12 = 0.9417; O =45.3/16=2.831= 45.3/16 = 2.831.

Step 2. Divide by the smallest value (0.9417): Na =1.887/0.9417=2.00= 1.887/0.9417 = 2.00; C =1.00= 1.00; O =2.831/0.9417=3.01= 2.831/0.9417 = 3.01. …

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