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Exercise · Q10

Q.Choose the most correct option.
The process SO2 → S2Cl2 is
a. Reduction b. Oxidation c. Neither oxidation nor reduction d. Oxidation and reduction

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Step 1. Find S's oxidation number in SO2. O is -2 (rule 3), 2 O atoms give -4; for the neutral molecule, ON(S) + (-4) = 0, so ON(S) = +4.

Step 2. Find S's oxidation number in S2Cl2. Cl is -1 in a halide bond (rule 5), 2 Cl atoms give -2; for the neutral molecule, 2 x ON(S) + (-2) = 0, so ON(S) = +1 per atom (average, rule 8). …

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