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Exercise · Q15

Q.Answer the following question.
In which chemical reaction does carbon exhibit variation of oxidation state from -4 to +4? Write balanced chemical reaction.

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Step 1. Find carbon's oxidation number in CH4. H is +1 (bonded to the non-metal C, rule 4), 4 H contribute +4; for the neutral molecule, ON(C) + 4(+1) = 0, so ON(C) = -4.

Step 2. Find carbon's oxidation number in CO2. O is -2, 2 O contribute -4; ON(C) + (-4) = 0, so ON(C) = +4.

Step 3. Confirm the span. Carbon moves from -4 all the way to +4 -- an 8-unit rise, the largest possible single-atom oxidation-number change for a common element, since -4 and +4 are carbon's lowest and highest normal oxidation states. …

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