Skip to content

Chemistry · Ch 4 — Structure of Atom

Explanation of the Line Spectrum of Hydrogen Using Bohr Theory

4.6.3

Explanation of the Line Spectrum of Hydrogen Using Bohr Theory

Bohr's theory does not just describe individual stationary states — it explains WHY hydrogen's emission spectrum shows exactly the lines it does. By Bohr's second postulate, radiation is emitted only when an electron falls from an outer orbit of higher principal quantum number (nin_i, the initial state) to an inner orbit of lower principal quantum number (nfn_f, the final state), and by the third postulate the energy of that emitted radiation equals the energy difference between the two orbits, ΔE=Ei−Ef\Delta E = E_i - E_f. Substituting the orbit-energy expression En=−RH(1n2)E_n = -R_H\left(\frac{1}{n^2}\right) for both EiE_i and EfE_f and simplifying gives ΔE=RH(1nf2−1ni2)\Delta E = R_H\left(\frac{1}{n_f^2}-\frac{1}{n_i^2}\right), and putting in RH=2.18×10−18R_H = 2.18\times10^{-18} J alongside E=hνE=h\nu and νˉ=ν/c\bar\nu = \nu/c converts this into a wavenumber expression, νˉ=109677(1nf2−1ni2) cm−1\bar\nu = 109677\left(\frac{1}{n_f^2}-\frac{1}{n_i^2}\right)\ \text{cm}^{-1} — which is exactly the empirical Rydberg equation from section 4.5.2, with nf=n1n_f = n_1 and ni=n2n_i = n_2. In other words, Bohr's theory doesn't just fit the Rydberg equation after the fact, it derives it from first principles, and in doing so gives the previously-empirical integers n1n_1 and n2n_2 real physical meaning: they are the principal quantum numbers of the final and initial concentric orbits of an electronic transition. Every one of the five named series (Lyman, Balm …

Figure 4.6Electronic transition in the hydrogen spectrum

What this figure shows. A term-diagram style figure showing the hydrogen atom's stationary-state energy levels stacked with increasing n, and arrows drawn between levels to show which electronic transitions produce which named series: transitions ending at n=1 (from n=2,3,4,...) produce the Lyman series; transitions ending at n=2 produce the Balmer series; ending at n=3 the Paschen series; ending at n=4 the Bracket series; ending at n=5 the Pfund series. The diagram is annotated with the ionisation enthalpy of hydrogen, 1312 kJ mol⁻¹ (the energy needed to remove the el …

Misc Problem 4.8Wavelength of the photon for the n=5 to n=2 transition

Worked out. Worked example: find the wavelength of the photon emitted when an electron falls from n=5 to n=2 in a hydrogen atom. Using the Rydberg wavenumber expression with n₁=2, n₂=5: νˉ=109677(122−152)=109677(14−125)=109677×21100=23032.17\bar\nu = 109677\left(\frac{1}{2^2}-\frac{1}{5^2}\right) = 109677\left(\frac{1}{4}-\frac{1}{25}\right) = 109677\times\frac{21}{100} = 23032.17 cm⁻¹. Then λ=1νˉ=123032.17\lambda = \frac{1}{\bar\nu} = \frac{1}{23032.17} cm =4.34×10−5= 4.34\times10^{-5} cm =4.34×10−5×107= 4.34\times10^{-5}\times10^{7} nm $ …