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Exercise 1.1 · Q3

Q.Convert the following angles into radian.

i) 85° ii) 250° iii) −132° iv) 65°30′ v) 75°30′ vi) 40°48′
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✓ Free question

Step 1: Use θ°=θ×π180\theta° = \theta\times\frac{\pi}{180} radian, simplifying the fraction each time. For the D-M measures, first write the minutes as a decimal degree (30′=0.5°30'=0.5°, 48′=0.8°48'=0.8°).

i) 85°=85×π180=17π3685° = 85\times\frac{\pi}{180} = \frac{17\pi}{36} (dividing by 55).

ii) 250°=250×π180=25π18250° = 250\times\frac{\pi}{180} = \frac{25\pi}{18} (dividing by 1010).

iii) −132°=−132×π180=−11π15-132° = -132\times\frac{\pi}{180} = -\frac{11\pi}{15} (dividing by 1212).

iv) 65°30′=65.5°=1312×π180=131π36065°30' = 65.5° = \frac{131}{2}\times\frac{\pi}{180} = \frac{131\pi}{360}.

v) 75°30′=75.5°=1512×π180=151π36075°30' = 75.5° = \frac{151}{2}\times\frac{\pi}{180} = \frac{151\pi}{360}.

vi) 40°48′=40.8°=2045×π180=204π900=17π7540°48' = 40.8° = \frac{204}{5}\times\frac{\pi}{180} = \frac{204\pi}{900} = \frac{17\pi}{75} (dividing by 1212).

✓Final answer

i) 17π36\frac{17\pi}{36} ii) 25π18\frac{25\pi}{18} iii) −11π15-\frac{11\pi}{15} iv) 131π360\frac{131\pi}{360} v) 151π360\frac{151\pi}{360} vi) 17π75\frac{17\pi}{75}

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