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Exercise 1.1 · Q4

Q.Convert the following angles into degree.

i) 7π12c\dfrac{7\pi}{12}^{c} ii) −5π3c\dfrac{-5\pi}{3}^{c} iii) 5c5^{c} iv) 11π18c\dfrac{11\pi}{18}^{c} v) −14c\dfrac{-1}{4}^{c}
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Step 1: Use θc=θ×180π\theta^{c} = \theta\times\frac{180}{\pi} degree.

i) 7π12×180π=7×15=105°\frac{7\pi}{12}\times\frac{180}{\pi} = 7\times15 = 105°.

ii) −5π3×180π=−5×60=−300°-\frac{5\pi}{3}\times\frac{180}{\pi} = -5\times60 = -300°.

iii) 5×180π=900π≈286.479°5\times\frac{180}{\pi} = \frac{900}{\pi} \approx 286.479°. Converting the decimal part: 0.479×60≈28.7′⇒0.7×60≈44′′0.479\times60\approx28.7' \Rightarrow 0.7\times60\approx44'', so ≈286°28′44′′\approx286°28'44''.

iv) 11π18×180π=11×10=110°\frac{11\pi}{18}\times\frac{180}{\pi} = 11\times10 = 110°. …

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