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Exercise 1.1 · Q6

Q.In △ABC\triangle ABC, if m∠A=7π36cm\angle A = \dfrac{7\pi}{36}^{c}, m∠B=120°m\angle B = 120°, find m∠Cm\angle C in degree and radian.

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Step 1: Convert m∠A=7π36cm\angle A = \frac{7\pi}{36}^{c} to degree: 7π36×180π=7×5=35°\frac{7\pi}{36}\times\frac{180}{\pi} = 7\times5 = 35°.

Step 2: Use the angle-sum property of a triangle: m∠A+m∠B+m∠C=180°m\angle A + m\angle B + m\angle C = 180°.

35°+120°+m∠C=180°⇒m∠C=180°−155°=25°35° + 120° + m\angle C = 180° \Rightarrow m\angle C = 180° - 155° = 25°. …

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