Skip to content
Miscellaneous Exercise 6 (II) · Q46

Q.Find the centre and radius of the circle x=3−4sin⁡θx=3-4\sin\theta, y=2−4cos⁡θy=2-4\cos\theta.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
61% · 46/75 Questions
✓ Free question

The equations x=3−4sin⁡θx=3-4\sin\theta, y=2−4cos⁡θy=2-4\cos\theta can be rewritten as x−3=−4sin⁡θx-3=-4\sin\theta and y−2=−4cos⁡θy-2=-4\cos\theta. Squaring and adding: (x−3)2+(y−2)2=16sin⁡2θ+16cos⁡2θ=16(x-3)^2+(y-2)^2=16\sin^2\theta+16\cos^2\theta=16 (using sin⁡2θ+cos⁡2θ=1\sin^2\theta+\cos^2\theta=1). This is the centre-radius form with centre (3,2)(3,2) and radius 44.

✓Final answer

Centre (3,2)(3,2), radius 44.

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.