Skip to content
Exercise 4.5 · Q112

Q.If A=[12−3−37−80−61]A = \begin{bmatrix} 1 & 2 & -3 \\ -3 & 7 & -8 \\ 0 & -6 & 1 \end{bmatrix}, B=[9−12−42540−3]B = \begin{bmatrix} 9 & -1 & 2 \\ -4 & 2 & 5 \\ 4 & 0 & -3 \end{bmatrix}, then find the matrix CC such that A+B+CA+B+C is a zero matrix.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
33% · 70/212 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Given A=[12−3−37−80−61]A = \begin{bmatrix} 1 & 2 & -3 \\ -3 & 7 & -8 \\ 0 & -6 & 1 \end{bmatrix}, B=[9−12−42540−3]B = \begin{bmatrix} 9 & -1 & 2 \\ -4 & 2 & 5 \\ 4 & 0 & -3 \end{bmatrix}, and A+B+C=OA+B+C=O (the zero matrix), so C=−(A+B)C=-(A+B).

First compute A+BA+B:

A+B=[1+92+(−1)−3+2−3+(−4)7+2−8+50+4−6+01+(−3)]=[101−1−79−34−6−2]A+B = \begin{bmatrix} 1+9 & 2+(-1) & -3+2 \\ -3+(-4) & 7+2 & -8+5 \\ 0+4 & -6+0 & 1+(-3) \end{bmatrix} = \begin{bmatrix} 10 & 1 & -1 \\ -7 & 9 & -3 \\ 4 & -6 & -2 \end{bmatrix} …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.