Skip to content
EXERCISE 9.1 · Q1

Q.x2+3x−1x^2+3x-1

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
1% · 1/75 Questions
✓ Free question

Let f(x)=x2+3x−1f(x)=x^2+3x-1, so f(x+h)=(x+h)2+3(x+h)−1=x2+2xh+h2+3x+3h−1f(x+h)=(x+h)^2+3(x+h)-1=x^2+2xh+h^2+3x+3h-1.

f(x+h)−f(x)=2xh+h2+3h=h(2x+h+3)f(x+h)-f(x)=2xh+h^2+3h=h(2x+h+3).

f(x+h)−f(x)h=2x+h+3\dfrac{f(x+h)-f(x)}{h}=2x+h+3.

Letting h→0h\to0: f′(x)=2x+3f'(x)=2x+3.

✓Final answer

f′(x)=2x+3f'(x)=2x+3

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.