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EXERCISE 9.1 · Q14

Q.cos⁡x\cos x at x=5π4x=\dfrac{5\pi}{4}

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Let f(x)=cos⁡xf(x)=\cos x. By first principles (proved in the 'Try the following' box), f′(x)=−sin⁡xf'(x)=-\sin x.

At x=5π4x=\dfrac{5\pi}4 (third quadrant): sin⁡5π4=−22\sin\dfrac{5\pi}4=-\dfrac{\sqrt2}2. …

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