Skip to content
EXERCISE 9.1 · Q2

Q.sin⁡(3x)\sin(3x)

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
3% · 2/75 Questions
✓ Free question

Let f(x)=sin⁡(3x)f(x)=\sin(3x), so f(x+h)=sin⁡(3x+3h)f(x+h)=\sin(3x+3h).

f(x+h)−f(x)=sin⁡(3x+3h)−sin⁡(3x)=2cos⁡ ⁣(3x+3h2)sin⁡ ⁣(3h2)f(x+h)-f(x)=\sin(3x+3h)-\sin(3x)=2\cos\!\left(3x+\dfrac{3h}2\right)\sin\!\left(\dfrac{3h}2\right).

f(x+h)−f(x)h=2cos⁡ ⁣(3x+3h2)⋅sin⁡(3h/2)h=3cos⁡ ⁣(3x+3h2)⋅sin⁡(3h/2)3h/2\dfrac{f(x+h)-f(x)}{h}=2\cos\!\left(3x+\dfrac{3h}2\right)\cdot\dfrac{\sin(3h/2)}{h}=3\cos\!\left(3x+\dfrac{3h}2\right)\cdot\dfrac{\sin(3h/2)}{3h/2}.

As h→0h\to0: →3cos⁡(3x)⋅1\to3\cos(3x)\cdot1.

✓Final answer

f′(x)=3cos⁡(3x)f'(x)=3\cos(3x)

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.