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EXERCISE 9.1 · Q11

Q.23x+12^{3x+1} at x=2x=2

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Let f(x)=23x+1f(x)=2^{3x+1}, so f(x+h)=23x+3h+1=23x+1⋅23h=23x+1⋅8hf(x+h)=2^{3x+3h+1}=2^{3x+1}\cdot2^{3h}=2^{3x+1}\cdot8^h.

f(x+h)−f(x)h=23x+1⋅8h−1h\dfrac{f(x+h)-f(x)}{h}=2^{3x+1}\cdot\dfrac{8^h-1}{h}.

As h→0h\to0: →23x+1log⁡8=23x+1⋅3log⁡2\to2^{3x+1}\log8=2^{3x+1}\cdot3\log2 (since 8=238=2^3, log⁡8=3log⁡2\log8=3\log2). …

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