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Mathematics · Ch 2 — Trigonometry - I

Periodicity of Trigonometric functions

2.2.2

Periodicity of Trigonometric functions

Periodicity of Trigonometric functions

A function f is periodic if there is a constant p>0p>0 such that f(x+p)=f(x)f(x+p)=f(x) for every x in its domain — so that f(x)=f(x+p)=f(x+2p)=⋯=f(x−p)=f(x−2p)=…f(x)=f(x+p)=f(x+2p)=\dots=f(x-p)=f(x-2p)=\dots. The smallest such positive p is called the fundamental period (or simply the period) of f.

Rotating an angle by one full revolution (2π2\pi radians) brings the terminal ray — and hence the point P and every coordinate-based trigonometric value — back to exactly where it started, so sin⁡(x+2π)=sin⁡x\sin(x+2\pi)=\sin x for every x. Since no smaller positive p works (sine strictly increases then decreases within each 2π2\pi stretch), sinx has period 2π2\pi; the same reasoning gives cosx, cosecx and secx period 2π2\pi.

Tangent and cotangent are different: rotating by half a revolution (π\pi) sends P to the diametrically opposite point (−x,−y)(-x,-y), and since tan⁡θ=y/x\tan\theta=y/x, both signs flip and cancel: tan⁡(x+π)=−y−x=yx=tan⁡x\tan(x+\pi) = \dfrac{-y}{-x} = \dfrac{y}{x} = \tan x for all x. So tanx and cotx have the shorter period π\pi.

Summary table

FunctionDomainRangePeriod
sinθℝ[−1, 1]2π
cosθℝ[−1, 1]2π
tanθℝ − {(2n+1)π/2 : n∈ℤ}ℝπ
cosecθℝ − {nπ : n∈ℤ}ℝ − (−1, 1)2π
secθℝ − {(2n+1)π/2 : n∈ℤ}ℝ − (−1, 1)2π
cotθℝ − {nπ : n∈ℤ}ℝπ

Solved Example 1 — find sin(41π/4)

Step 1. Write 41π4\tfrac{41\pi}{4} as a whole multiple of the period 2π=8π42\pi=\tfrac{8\pi}{4} plus a remainder: 41π4=40π4+π4=10π+π4\tfrac{41\pi}{4} = \tfrac{40\pi}{4}+\tfrac{\pi}{4} = 10\pi+\tfrac{\pi}{4}, and 10π=5×2π10\pi = 5\times2\pi is five full periods. …

Figure 2.20One period of cotθ

What this figure shows. A sketch of y = cotθ over one period, decreasing steadily from +∞ to −∞ between consecutive multiples of π, illustrating that cotθ repeats with period π and is undefined at …

Table T2Domain, range and period of the six trigonometric functions

sinθ: domain R, range [−1,1], period 2π | cosθ: domain R, range [−1,1], period 2π | tanθ: domain R−{(2n+1)π/2 : n∈I}, range R, period π | cosecθ: domain R−{nπ : n∈I}, range R−(−1,1), period 2π | secθ: domain R−{(2n+1)π/2 : n∈I}, range R−(−1,1), period 2π …

Misc S10Solved Example 1 — find sin(41π/4)

Worked out. Writes 41π/4 as a whole multiple of 2π plus a small remainder angle, then uses the 2π-periodicity of sine to reduce the value to the sine of the remainder angle. …

Misc S11Solved Example 2 — find cos765°

Worked out. Writes 765° as a whole multiple of 360° plus a small remainder angle, then uses the 360°-periodicity of cosine to reduce the value to the cosine of the remainder angle. …