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Exercise 2.2 · Q28

Q.If 2cos⁡2θ−11cos⁡θ+5=02\cos^2\theta − 11\cos\theta + 5 = 0, then find possible values of cos⁡θ\cos\theta.

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Step 1. 2cos⁡2θ−11cos⁡θ+5=02\cos^2\theta-11\cos\theta+5=0 factors as (2cos⁡θ−1)(cos⁡θ−5)=0(2\cos\theta-1)(\cos\theta-5)=0. …

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