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Exercise 2.2 · Q46

Q.Prove that (1+cot⁡θ−cosec θ)(1+tan⁡θ+sec⁡θ)=2(1 + \cot\theta − \text{cosec}\,\theta)(1 + \tan\theta + \sec\theta) = 2.

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Step 1. 1+cot⁡θ−cosec θ=sin⁡θ+cos⁡θ−1sin⁡θ1+\cot\theta-\text{cosec}\,\theta = \dfrac{\sin\theta+\cos\theta-1}{\sin\theta}.

Step 2. 1+tan⁡θ+sec⁡θ=cos⁡θ+sin⁡θ+1cos⁡θ1+\tan\theta+\sec\theta = \dfrac{\cos\theta+\sin\theta+1}{\cos\theta}.

Step 3. Product =(sin⁡θ+cos⁡θ−1)(sin⁡θ+cos⁡θ+1)sin⁡θcos⁡θ=(sin⁡θ+cos⁡θ)2−1sin⁡θcos⁡θ=\dfrac{(\sin\theta+\cos\theta-1)(\sin\theta+\cos\theta+1)}{\sin\theta\cos\theta} = \dfrac{(\sin\theta+\cos\theta)^2-1}{\sin\theta\cos\theta}. …

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