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Exercise 2.2 · Q29

Q.Find the acute angle θ such that 2cos⁡2θ=3sin⁡θ2\cos^2\theta = 3\sin\theta.

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Step 1. 2cos⁡2θ=3sin⁡θ⇒2(1−sin⁡2θ)=3sin⁡θ⇒2sin⁡2θ+3sin⁡θ−2=02\cos^2\theta=3\sin\theta \Rightarrow 2(1-\sin^2\theta)=3\sin\theta \Rightarrow 2\sin^2\theta+3\sin\theta-2=0. …

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