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Exercise 3.2 · Q23

Q.Find the value of: sin⁡690°\sin690°

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✓ Free question

Step 1: 690°=720°−30°690°=720°-30°, and 720°720° is a multiple of 360°360°, so sin⁡690°=sin⁡(−30°)=−sin⁡30°=−12\sin690°=\sin(-30°)=-\sin30°=-\dfrac{1}{2}.

✓Final answer

sin⁡690°=−12\sin690°=-\dfrac{1}{2}

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