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Exercise 3.2 · Q37

Q.Prove the following: tan⁡(π+x)sec⁡(2π−x)sin⁡(−x)cos⁡(3π2+x)cos⁡(2π−x) cosec x=tan⁡3x\dfrac{\tan(\pi+x)\sec(2\pi-x)\sin(-x)}{\cos\left(\dfrac{3\pi}{2}+x\right)\cos(2\pi-x)\,\text{cosec}\,x}=\tan^3x

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Concept understanding — Trigonometric Functions of Allied Angles

Allied angles are angles whose sum or difference with a given angle θ\theta is an integer multiple of π2\dfrac{\pi}{2} — i.e. −θ, π2±θ, π±θ, 3π2±θ, 2π±θ-\theta,\ \dfrac{\pi}{2}\pm\theta,\ \pi\pm\theta,\ \dfrac{3\pi}{2}\pm\theta,\ 2\pi\pm\theta. Every trigonometric ratio of an allied angle equals ±\pm the same or the co-ratio of θ\theta, obtained instantly from the compound-angle formulas of the previous concept. The working rule: (i) write the given angle as n⋅90°±θn\cdot90°\pm\theta for the smallest possible acute θ\theta; (ii) if nn is even, the ratio name stays the same (sin stays sin); if nn is odd, the ratio changes to its co-ratio (sin becomes cos, tan becomes cot); (iii) the sign is decided by the quadrant in which …

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